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Oksanka [162]
3 years ago
11

HELPPPPP

Biology
2 answers:
Bess [88]3 years ago
5 0

If the half-life is 80,000 years, then 240,000 years would be equivalent to three half-lives. In other words, the initial amount of the radioactive calcium-41 would have been reduced in half three times over. Mathematically, this can expressed as

calcium-41 remaining = initial mass of calcium-41 × (0.5)³.

Since we are given the initial mass of calcium-41, the amount of calcium-41 remaining after 240,000 years would be:

60 μg × (0.5)³ = 7.5 μg, or 7.5 micrograms.

kondor19780726 [428]3 years ago
3 0
7.5 is the answer I think hope this helps
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