What is equivalent too 48j +36
1 answer:
You might be interested in
X= 8.29 or 8.3
you have to use the pythagorean theorem (a^2 +b^2=c^2) remember c is the hypotenuse and the hypotenuse is always across from your triangles right angle
you have to use the pythagorean theorem (a^2 +b^2=c^2) remember c is the hypotenuse and the hypotenuse is always across from your triangles right angle
Answer:
168 trumpets for $1702
Step-by-step explanation:
Profit is the measure to be maximized. We are given revenue and cost relationships as a function of units, x (trumpets). Profit is the difference:
Profit = Revenue[R(x)] - Cost[C(x)]
Profit = (76x – 0.25x^2) - (-7.75x + 5,312.5)
Profit = 76x - 0.25x^2 + 7.75x - 5,312.5
Profit = 76x - 0.25x^2 + 7.75x - 5,312.5
Profit = - 0.25x^2 + 83.75x - 5312.5
At this point we can find the trumpets needed for maximum profit by either of two approaches: algebraic and graphing. I'll do both.
<u>Mathematically</u>
The first derivative will give us the slope of this function for any value of x. The maximum will have a slope of zero (the curve changes direction at that point). Take the first derivative and set that equal to 0 and solve for x.
First derivative:
d(Profit)/dx = - 2(0.25x) + 83.75
d(Profit)/dx = - 0.50x + 83.75
0 = - 0.50x + 83.75
0.50x = 83.75
x = 167.5 trumpets
<u>Graphically</u>
Plot the profit function and look for the maximum. The graph is attached. The maximum is 167.5 trumpets.
Round up or down to get a whole trumpet. I'll go up: 168 trumpets.
<u>Maximum Profit</u>
Solve the profit equation for 168 trumpets:
Profit = - 0.25x^2 + 83.75x - 5312.5
Profit = - 0.25(168)^2 + 83.75(168) - 5312.5
<u>Profit = $1702</u>
Answer:
a) (1, 2) not on the graph.
b) (1, -1) is on the graph.
Step-by-step explanation:
Given the equation of the line as:
The points given are
a) (1, 2)
To determine whether it is on the graph of the line or not.
To do so, we can do 2 things:
1. Draw the graph and plot the point on the graph to check whether it is on the graph or not.
2. To put the point in the given equation of the line, whether the equation is satisfied or not.
For method 1: Kindly refer to the attached image of the line and point plotted.
Method 2:
Let us put in the Left Hand Side (LHS) of equation.
(1, 2) Not on the graph.
(b) (1, -1)
For method 1: Kindly refer to the attached image of the line and point plotted.
Method 2:
Let us put in the Left Hand Side (LHS) of equation.
(1, -1) is on the graph.
