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2 years ago

Which is a possible turning point for the continuous function f(x)?

Mathematics

1 answer:

babymother [125]2 years ago

5 0

Answer:

We are given coordinates of a continuous function f(x)

(–2, 0)

(0, –2)

(2, –1)

(4, 0).

We need to find the possible turning point for the continuous function.

Note: Turning point is a point on the graph where slope of the curve changes from negative to positive or positive to negative.

A turning point is always lowest or highest point of the curve (where bump of the graph seen).

For the given coordinates we can see that (–2, 0) and (4, 0) coordinates are in a same line, that is on the x-axis.

But the coordinate (0, –2) is the lowest point on the graph.

Therefore, (0, –2) is the turning point for the continuous function given.

hoped this was helpful!

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Lily is a botanist who works for a garden that many tourists visit. The function f(s) = 2s + 30 represents the number of flowers

Vesnalui [34]

Answer:

A. b(w) = 80w +30

B. input: weeks; output: flowers that bloomed

C. 2830

Step-by-step explanation:

For f(s) = 2s +30, and s(w) = 40w, the composite function f(s(w)) is ...

b(w) = f(s(w)) = 2(40w) +30

b(w) = 80w +30 . . . . . . blooms over w weeks

The input units of f(s) are <em>seeds</em>. The output units are <em>flowers</em>.

The input units of s(w) are <em>weeks</em>. The output units are <em>seeds</em>.

Then the function b(w) above has input units of <em>weeks</em>, and output units of <em>flowers</em> (blooms).

For 35 weeks, the number of flowers that bloomed is ...

b(35) = 80(35) +30 = 2830 . . . . flowers bloomed over 35 weeks

7 0

1 year ago

20 POINTS

victus00 [196]

Ni is not correct. To solve the equivalent quarterly interest rate, the annual interest rate should be multiplied by the correct ratio. Since the annual interest rate is 4% per year. So in 1 quarter is equal to 0.25 year.

<span>(4% / year) (0.25 year/ 1 quarter) = 1% per quarter</span>

8 0

2 years ago

3c/4 - 2c/4 = 4 (solve with work please)

xxMikexx [17]

Simplifying

2c + 3 = 3c + -4

Reorder the terms:

3 + 2c = 3c + -4

Reorder the terms:

3 + 2c = -4 + 3c

Solving

3 + 2c = -4 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.

3 + 2c + -3c = -4 + 3c + -3c

Combine like terms: 2c + -3c = -1c

3 + -1c = -4 + 3c + -3c

Combine like terms: 3c + -3c = 0

3 + -1c = -4 + 0

3 + -1c = -4

Add '-3' to each side of the equation.

3 + -3 + -1c = -4 + -3

Combine like terms: 3 + -3 = 0

0 + -1c = -4 + -3

-1c = -4 + -3

Combine like terms: -4 + -3 = -7

-1c = -7

Divide each side by '-1'.

c = 7

Simplifying

c = 7

3 0

2 years ago

I need help solving this equation<br> 4n-9=2(5+2n)

Nastasia [14]

First, use distributive property on the right half.

2 * 5 = 10

2 * 2n = 4n

4n - 9 = 10 + 4n

Add 9 to both sides

4n = 19 + 4n

Subtract 4n from both sides

0 = 19

But thats not true. Therefore, there is no solution.

4 0

2 years ago

In 2009 there was an endangered population of 270 cranes in a western state. Due to wildlife efforts, the population is increasi

Vitek1552 [10]

Assuming compount interest format

$A=P(r+1)^t$ for compounded per 1 year
A=future amount
P=present amount
r=rate in decimal
t=time in years

given
P=270
r=5%=0.05

the equaton is
$A=270(0.05+1)^t$ or
$A=270(1.05)^t$
for any year, 2009, is year 0, so if you wanted to input the year then
$A=270(1.05)^{t-2009}$ would be for t=what year it was

A. $f(x)=270(1.05)^t$

b. 2009 to 2020
2020-2009=11 years
t=11
$f(11)=270(1.05)^{11}$
f(11)=461.792
about 462 cranes

A. $f(x)=270(1.05)^t$
B. about 462

8 0

2 years ago