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2 years ago

MARKING PEOPLE AS BRIANLIST

2 answers:

5 0

Answer; i believe it is C. circumcenter.

explanation; the circumcenter is something that is not always inside of a triangle, unlike the centroid, which is always found. the point of concurrency of the angle bisectors defines the incenter, which leads me to believe that the answer is C.

nlexa [21]2 years ago

4 0

Answer:

all of those are shown inside of the triangle ...

Step-by-step explanation:

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What is revenue from property taxes usually used for?

grandymaker [24]

Revenue from property taxes is used to fund all the services the municipal government provides us with, such as building a new park in the neighbourhood.

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3 years ago

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Which number is a common factor of 84 and 144?

schepotkina [342]

Your answer would be 12

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3 years ago

Which equation represents a non-proportional situation? y = 6x y = –2x + 14 y = –3x y = 14x

ki77a [65]

The equation of proportional situation is y = ax.

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3 years ago

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What is the rate of change of the volume of the cylinder at that instance (in cubic kilometers per second)?

Kay [80]

Answer:

hello your question is incomplete attached below is the complete question

answer : -2400 π

Step-by-step explanation:

dr/dt = -12 km/s

h = 2.5 km

r = 40 km at some instant

hence the rate of change of Volume of cylinder at that instance

= dv / dt = $d(\pi r^h ) / dt$

= $\pi h\frac{d(r^2)}{dt}$ = $-\pi h *2r *dr/dt$

hence ; dv / dt = -2400 π

3 0

2 years ago

URGENT: If θ is a second-quadrant angle and cosθ = -2/3, then tanθ = _____.

dangina [55]

In the second quadrant, both cos and tan are negative while only sin is positive.

To find tan, we will use the following property below:

$\large \boxed{ {tan}^{2} \theta = {sec}^{2} \theta - 1}$

Sec is the reciprocal of cos. If cos is a/b then sec is b/a. Since cos is 2/3 then sec is 3/2

$\large{ {tan}^{2} \theta = {( - \frac{3}{2}) }^{2} - 1} \\ \large{ {tan}^{2} \theta = \frac{9}{4} - 1} \\ \large{ {tan}^{2} \theta = \frac{9}{4} - \frac{4}{4} \longrightarrow \frac{5}{4} } \\ \large{tan \theta = \frac{ \sqrt{5} }{ \sqrt{4} } } \\ \large \boxed{tan \theta = \frac{ \sqrt{5} }{2} }$

Since tan is negative in the second quadrant. Hence,

$\large{ \cancel{ tan \theta = \frac{ \sqrt{5} }{2} } \longrightarrow \boxed{tan \theta = - \frac{ \sqrt{5} }{2} }}$

Answer

tan = -√5/2

3 0

2 years ago