<span>circumference of circle = 2*pi*r
given r = 5
so circumference = 31.42
now we know 360 degree is uniformly distributed on this circumference
so x/360=10/31.42
so x= 114.65
so option C.) 114.65 is the answer</span>
20% =20/100=2/10
20% of 400 =(2/10)*400 =80
1/4 of 360= (1/4)*360 =90
90>80, so 1/4 of 360 is bigger than 20% of 400
Answer:
$2.046
Step-by-step explanation: I think..don't take my word.
Answer:
Step-by-step explanation:
As we know that from a theorem,
A greater angle of a triangle is opposite a greater side. Let ABC be a triangle in which angle ABC is greater than angle BCA; then side AC is also greater than side AB. For if it is not greater, then AC is either equal to AB or less.
As we have angle A =120 so it means the other 2 angles will be less than angle A , hence the opposite side to angle A is BC ,
Hence BC line is the longest line in triangle ABC
Essentially, what we need to do here is prove that BE=EC, BE=CB, and.or CE=BC therefore making it isosceles. With ∠AEC=∠DEB, we know AE=DE, so EC=EB (the points go in order). Therefore, as EC=EB, BEC is isosceles (it has at least 2 equal sides).
Feel free to ask further questions!
