Let numbers of books be 'b' and numbers of CDs be 'c'
We can set up two equations:
Equation [1] ⇒

Equation [2] ⇒

We are solving for the number of books and the number of CDs bought
When we have two equations in terms of two different variables;

and

, that we need to solve, then this becomes a simultaneous equation problem.
First, rearrange Equation [1] to make either

or

the subject:


Then we substitute

into Equation [2]






Now we know the value of

which is

, substitute this value into

we have

Answer:
Numbers of books = 13
Numbers of CDs = 7
Answer:
7
Step-by-step explanation:
20 • 35% = 13 20-13=7
It would be 2.4 times 10. I got this answer because there is 24 shaded in, so I divided it by 10 and got 2.4. The other answers could also be 6 times 4, 8 times 3, 2 times 12, 1 times 24. I hope this helps. <3
A + b = 15 ..... eq 1
a – b = 12 ...... eq 2
So a = 15 – b
Substitute in eq 2 :
15 – b – b = 12
15 – 2b = 12
–2b = 12 – 15
b = 1.5
So a = 15 – 3/2 = 13.5
4ab = 4 x 13.5 x 1.5 = 81
Answer:
-1.615 is the answer...
Step-by-step explanation:
Hope this helps....