Answer:
danny's offer is cheaper
Step-by-step explanation:
danny = $9 per hour
martin = $16 per hour
Answer:
The electric field generated by a point charge is given by:
where
is the Coulomb's constant
Q is the charge
r is the distance from the charge
We want to know the net electric field at the midpoint between the two charges, so at a distance of r=5.0 cm=0.05 m from each of them.
Let's calculate first the electric field generated by the positive charge at that point:
where the positive sign means its direction is away from the charge.
while the electric field generated by the negative charge is:
where the negative sign means its direction is toward the charge.
If we assume that the positive charge is on the left and the negative charge is on the right, we see that E1 is directed to the right, and E2 is directed to the right as well. This means that the net electric field at the midpoint between the two charges is just the sum of the two fields:
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Step-by-step explanation:
Hello,
Let's place the last digit: it must be 2 or 4 or 8 (3 possibilities)
It remainds 4 digits and the number of permutations fo 4 numbers is 4!=4*3*2*1=24
Thus there are 3*24=72 possibilities.
Answer A
If you do'nt believe run this programm
DIM n(5) AS INTEGER, i1 AS INTEGER, i2 AS INTEGER, i3 AS INTEGER, i4 AS INTEGER, i5 AS INTEGER, nb AS LONG, tot AS LONG
tot = 0
n(1) = 1
n(2) = 2
n(3) = 4
n(4) = 7
n(5) = 8
FOR i1 = 1 TO 5
FOR i2 = 1 TO 5
IF i2 <> i1 THEN
FOR i3 = 1 TO 5
IF i3 <> i2 AND i3 <> i1 THEN
FOR i4 = 1 TO 5
IF i4 <> i3 AND i4 <> i2 AND i4 <> i1 THEN
FOR i5 = 1 TO 5
IF i5 <> i4 AND i5 <> i3 AND i5 <> i2 AND i5 <> i1 THEN
nb = ((((n(i1) * 10) + n(i2)) * 10 + n(i3)) * 10 + n(i4)) * 10 + n(i5)
IF nb MOD 2 = 0 THEN
tot = tot + 1
END IF
END IF
NEXT i5
END IF
NEXT i4
END IF
NEXT i3
END IF
NEXT i2
NEXT i1
PRINT "tot="; tot
END
8.517 as a Fraction:8 and 500/1000 ( This is a mixed number)
8.517 as a Percentage: 815.7%
Answer:
So the numbers are 12 and -3.
Step-by-step explanation:
In order to solve this problem we will attribute variables to the numbers, the first one will be "x" and the second one will be "y". From the first sentence we know that the subtraction of the two numbers is equal to 15, so we have:
x - y = 15
Then the problem states that one-third of the sum of the number is equal to one quarter of the first number, so we have:
(1/3)*(x+y) = x/4
Since we now have two equations and two variables we can solve for x and y. From the first equation we have:
y = x - 15
Using this expression for the value of y in the second equation:
(1/3)*(x + x - 15) = x/4
(1/3)*(2*x - 15) = x/4
2*x - 15 = 3*x/4
2*x - 3*x/4 = 15
(8*x - 3*x)/4 = 15
5*x/4 = 15
5*x = 60
x = 60/5 = 12
y = x - 15 = 12 - 15 = -3
So the numbers are 12 and -3.
