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3 years ago

How do I get y equals by itself in the equation 2x+5y=20

Mathematics

2 answers:

Likurg_2 [28]3 years ago

6 0

Answer:

Subtract 2x to bring it to the other side

Step-by-step explanation:

2x+5y=20

-2x. -2x

5y=-2x+20

ruslelena [56]3 years ago

3 0

Answer: subtract 2x from that side to get 5y= 20-2x

Step-by-step explanation:

You subtract to get 5y = 20-2x. If you want y completely by itself divide it all by 5. 5y divides by 5, 20 divided by 5 and -2x by 5.

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Tom [10]

D because if it says -3 that means the opposite so go right because it is also horizontal and + means up so go up because it is vertical.

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3 years ago

9-3 divided by 1/3 +1

Andrei [34K]

Nine thirds? If so its would be 9/3 / 1/3?

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3 years ago

Read 2 more answers

Use the zero product property to find the solutions to the equation x^2+x-30=12

lukranit [14]

Answer:

Due to there being no negatives in this equation, you can pretty much just eliminate the first 3 answers.

However in working out, here is what I did.

x^2 + x - 30 = 12 (+30)

= x^2 + x = 42

Then you can conclude that the answer is D, due to 6 x 6 = 36, plus 7 equaling 42.

8 0

3 years ago

How can Diego package all the 64 cookies so that each bag has the same number of them? How many bags can we make and how many co

anygoal [31]

Answer:

see below

Step-by-step explanation:

There are 7 divisors of 64. Each represents a possible number of bags of cookies:

1 bag of 64 cookies
2 bags of 32 cookies
4 bags of 16 cookies
8 bags of 8 cookies
16 bags of 4 cookies
32 bags of 2 cookies
64 bags of 1 cookie

5 0

3 years ago

he amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and s

sp2606 [1]

Complete question:

He amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.3 minutes and standard deviation 1.4 minutes. Suppose that a random sample of n equals 47 customers is observed. Find the probability that the average time waiting in line for these customers is

a) less than 8 minutes

b) between 8 and 9 minutes

c) less than 7.5 minutes

Answer:

a) 0.0708

b) 0.9291

c) 0.0000

Step-by-step explanation:

Given:

n = 47

u = 8.3 mins

s.d = 1.4 mins

a) Less than 8 minutes:

$P(X$

P(X' < 8) = P(Z< - 1.47)

Using the normal distribution table:

NORMSDIST(-1.47)

= 0.0708

b) between 8 and 9 minutes:

P(8< X' <9) = $[\frac{8-8.3}{1.4/ \sqrt{47}}< \frac{X'-u}{s.d/ \sqrt{n}} < \frac{9-8.3}{1.4/ \sqrt{47}}]$

= P(-1.47 <Z< 6.366)

= P( Z< 6.366) - P(Z< -1.47)

Using normal distribution table,

$NORMSDIST(6.366)-NORMSDIST(-1.47)$

0.9999 - 0.0708

= 0.9291

c) Less than 7.5 minutes:

P(X'<7.5) = $P [Z< \frac{7.5-8.3}{1.4/ \sqrt{47}}]$

P(X' < 7.5) = P(Z< -3.92)

NORMSDIST (-3.92)

= 0.0000

3 0

3 years ago