The formula for depreciation is:
Where x = Initial value,
y= Amount after depreciation.
r= Rate of depreciation,
t = time (in years)
According to given problem,
x = 1040, y= 944 and t = 12 months =1 year.
So, first step is to plug in these values in the above formula, So,
944 = 1040 (1 -r)
Divide each sides by 1040.
0.907692308 =1 - r
0.907692308 - 1 = -r Subtract 1 from each sides.
-0.092307692 = -r
So, r = 0.09 or 9%.
Now plug in 0.09 in the above equation to get the depreciation equation. So,
So, 
b) To find the value of the bike after 5 months,
plug in t = 5 months= 5/12 = 0.41667 years in the above equation of depreciation.
So, 
y = 1040 * 0.961465659
y = 999.9242852
y = 1000 (Rounded to nearest integer).
Hence, the value of the bike after 5 months is $1000.
It could be 28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43, or 44.
The ratio is 9 : 7 which means for every 9 pounds of Quartz you have 7 pounds Marble. For the second row Quartz is 72. For the third row it's 11 bags because 99/9 = 11 and 11 times 7 equals 77. The four one is 126 pounds Quartz. Finally the last one is 15 bags and 15 times 7 is 75 pounds of Marble. What you do with the ratio is multiply by the number of bags to figure out with this many bags how many Quartz or Marble. You can do the same thing to figure out how many bags.
Answer:
Tn = 3n-1
T6 = 17
Step-by-step explanation:
Given the arithmetic sequence;
2, 5...
first term a = 2
Common difference d = 5-2 = 3
nth term of an AP is expressed as Tn = a + (n-1)d
Tn = 2 + (n-1)(3)
Tn = 2 + 3n-3
Tn = 3n-1
Get the 6th term
T6 = 3(6)-1
T6 = 18-1
T6 = 17
Hence the 6th term of the sequence is 17
A quadratic equation is an equation whose leading coefficient is of second degree. The time can not be negative, therefore, the time in which the athlete complete the jump is 0.75 seconds.
<h3>What is a quadratic equation?</h3>
A quadratic equation is an equation whose leading coefficient is of second degree also the equation has only one unknown while it has 3 unknown numbers. It is written in the form of ax²+bx+c.
The jump is represented by the equation h(x)= -16x²+4x+6. The time is represented by x, now the height of the athlete will be zero when the jump will be completed therefore, we can write,
0 = - 16x² + 4x + 6
0 = - 16x² + 12x - 8x + 6
0 = -4x(4x-3) -2(4x-3)
0 = (-4x-2)(4x-3)
x = -0.50, 0.75
Since the time can not be negative, therefore, the time in which the athlete complete the jump is 0.75 seconds.
Learn more about Quadratic Equations:
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