All categories

3 years ago

Help idk what the answer is!!!

Mathematics

1 answer:

Vlad [161]3 years ago

5 0

D. y=x+2 is the correct answer because if you add two to the x values you get y.

You might be interested in

You are hosting a convention for a charitable organization. You pay a rental fee of $28,500 for the convention center, plus you

Alexxandr [17]

You have to add the $51 to $13 and find the answer then divide the sum by $28,500

8 0

3 years ago

Read 2 more answers

.At a certain animal shelter, the ratio of puppies to adult dogs is 7 to 4. This week there are a total of55 dogs in the shelter

Advocard [28]

Answer:

There are 35 adult dogs and 20 puppies

Step-by-step explanation:

Represent the puppies with P and the Adult dogs with A

Given

$A : P = 7 : 4$

Dogs = 55

Required

Determine A and P

First, we need to sum the ratios;

$Total = A + P$

$Total = 7 + 4$

$Total = 11$

Adult Dogs is then calculated as follows;

$A = \frac{A\ Ratio}{Total} * Dogs$

$A = \frac{7}{11} * 55$

$A = \frac{385}{11}$

$A = 35$

Puppies is calculated by subtracting the number of adult dogs from the total

$P = Dogs - Adult\ Dogs$

$P = 55 - 35$

$P = 20$

Hence;

There are 35 adult dogs and 20 puppies

3 0

3 years ago

How do I need to do this question?

lesya [120]

Answer:

exactly what it says

Step-by-step explanation:

you see the numbers on f and g??

(F x G)x(-1)

3 0

2 years ago

In Vancouver, British Columbia, the probability of rain during a winter day is 0.42, for a spring day is 0.23, for a summer day

nadezda [96]

Answer:

31.82% probability that this day would be a winter day

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening

In this question:

Event A: Rain

Event B: Winter day

Probability of rain:

0.42 of 0.25(winter), 0.23 of 0.25(spring), 0.16 of 0.25(summer) or 0.51 of 0.25(fall).

$P(A) = 0.42*0.25 + 0.23*0.25 + 0.16*0.25 + 0.51*0.25 = 0.33$

Intersection:

Rain on a winter day, which is 0.42 of 0.25. So

$P(A \cap B) = 0.42*0.25 = 0.105$

If you were told that on a particular day it was raining in Vancouver, what would be the probability that this day would be a winter day?

$P(B|A) = \frac{0.105}{0.33} = 0.3182$

31.82% probability that this day would be a winter day

6 0

3 years ago

PLEASE HELPPPPPP ASAPPPPP !!!

8_murik_8 [283]

Answer:

just to be clear ill help you with anything ;)

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers