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krek1111 [17]
3 years ago
5

Yoo wasup am i the only bored one here?

Mathematics
2 answers:
sertanlavr [38]3 years ago
8 0

Answer:

Nah fam, it fr be like that

Kisachek [45]3 years ago
3 0

Answer:

nah me too

Step-by-step explanation:

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I need help to solve this multi step equation please give me the correct answer
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291 - 5y

Step-by-step explanation:

x- a measure of the fourth angle

The equation

x+60+(2y+8)+(3y+1)=360\qquad|\text{combine like terms}\\\\x+(2y+3y)+(60+8+1)=360\\\\x+5y+69=360\qquad|\text{subtract 5y and 69 from both sides}\\\\x=291-5y

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Which inequality is true? Use the number line to help.
PolarNik [594]

Answer:

C) -1.5 < -0.5

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QUESTION IN PHOTO, HELP ASAP
Luba_88 [7]
I don’t get the question? What are you trying to find?
6 0
2 years ago
Use the factors of the function and the y-intercept to find the standard form of the equation representing Jared’s function. Typ
Georgia [21]

The y-intercept of a function is the point where the graph crosses the \mathbf{y = x^3 + 2x^2 - 193x - 270 }

  • The factors of the Jared's graph are: (x - 10), (x + 3) and (x + 9)
  • The y-intercept is -13.5
  • The standard equation of the function is: \mathbf{y = x^3 + 2x^2 - 193x - 270 }

<u>(a) The factors</u>

First, we write out the points where the function cross the x-axis.

The points are:

\mathbf{x = 10}

\mathbf{x = -3}

\mathbf{x = -9}

Equate the above points to 0

\mathbf{x -10 = 0}

\mathbf{x +3 = 0}

\mathbf{x +9 = 0}

Hence, the factors are: (x - 10), (x + 3) and (x + 9)

<u>(b) The y-intercept</u>

This is the point where the graph crosses the y-axis.

From the attached graph, the graph crosses the y-axis at -13.5.

Hence, the y-intercept is -13.5

<u>(c) The standard form</u>

In (a), we have:

\mathbf{x -10 = 0}

\mathbf{x +3 = 0}

\mathbf{x +9 = 0}

Multiply the above equations

\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 \times 0 \times 0}

\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 }

Expand

\mathbf{(x - 10) \times (x^2 + 3x + 9x + 27) = 0 }

\mathbf{(x - 10) \times (x^2 + 12x + 27) = 0 }

Expand

\mathbf{x^3 + 12x^2 + 27x - 10x^2 - 220x - 270 = 0 }

Collect like terms

\mathbf{x^3 + 12x^2 - 10x^2+ 27x  - 220x - 270 = 0 }

\mathbf{x^3 + 2x^2 - 193x - 270 = 0 }

Replace 0 with y

\mathbf{y = x^3 + 2x^2 - 193x - 270 }

Hence, the standard form is: \mathbf{y = x^3 + 2x^2 - 193x - 270 }

Read more about graphs and functions at:

brainly.com/question/18806107

3 0
2 years ago
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