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2 years ago

Yoo wasup am i the only bored one here?

Mathematics

2 answers:

sertanlavr [38]2 years ago

8 0

Answer:

Nah fam, it fr be like that

Kisachek [45]2 years ago

3 0

Answer:

nah me too

Step-by-step explanation:

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The perimeter of a parallelogram is 76 inches and 1 side measures 14 inches of it can be determined what are the lengths in inch

nydimaria [60]

The dimension of the parallelogram ABCD will be 14 inches, 48 inches, 14 inches and 48 inches.

<h3>What is a parallelogram?</h3>

It is a polygon with four sides. The total interior angle is 360 degrees. A parallelogram's opposite sides are parallel and equal.

The perimeter of a parallelogram is 76 inches.0

And one side measure is 14 inches.

Then the rest of the sides will be

We know that opposite sides are prallel and equal.

Let ABCD is a parallelogram.

AB = CD = 14 inches

BC = AD = x

Then the value of x will be

We know

P = 2(AB + BC)

76 = 2(14 + x)

x = 48

More about the parallelogram link is given below.

brainly.com/question/1563728

#SPJ1

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1 year ago

PLZ HELP ME I WILL GIVE BRAINLIEST....

guapka [62]

Answer:

A. 2, 3, and 4

B: 4

Step-by-step explanation:

4 0

2 years ago

Write the next three terms in the pattern. What is each pattern rule?

Lelechka [254]

-70, -100, +20

Step by step explanation: Follow the pattern.

5 0

2 years ago

Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2

Andre45 [30]

For this case, we must indicate which of the given functions is not defined for $x = 0$

By definition, we know that:

$f (x) = \sqrt {x}$ has a domain from 0 to infinity.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

$y = \sqrt {x-2}$ is not defined, the term inside the root is negative when $x = 0$ .

While $y = \sqrt {x + 2}$ if it is defined for $x = 0.$

$f(x)=\sqrt[3]{x}$ , your domain is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root.

So, we have:

$y = \sqrt [3] {x-2}$ with x = 0: $y = \sqrt [3] {- 2}$ is defined.