3 years ago

262 + 923 + 231 - 138 = ?

Mathematics

1 answer:

ikadub [295]3 years ago

7 0

Answer: 1278

Step-by-step explanation:

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Answer:

$6\sqrt{3}i-6j$

Step-by-step explanation:

Given:

The magnitude, v=12

The angle $\alpha$ it makes with the positive x-axis = $150^0$

Now for a vector (x,y)

$\alpha =tan^{-1}(\frac{y}{x} )$ ; and

$v=\sqrt{x^2+y^2}$

Therefore:

$150 =tan^{-1}(\frac{y}{x} )\\\frac{y}{x} =tan 150\\\frac{y}{x}=-\frac{\sqrt{3} }{3}$

$y=-\frac{x \sqrt{3}}{3}$

Similarly:

$v=\sqrt{x^2+y^2}\\12=\sqrt{x^2+y^2}\\12^2=x^2+y^2\\144=x^2+y^2$

$144=x^2+(-\frac{x \sqrt{3}}{3} )^2\\144=x^2+\frac{3x^2}{9} \\144=\frac{4x^2}{3}\\4x^2=144 X 3=432\\x^2=108\\x=6\sqrt{3}$

Recall that:

$y=-\frac{x \sqrt{3}}{3}\\y=-\frac{6\sqrt{3} \sqrt{3}}{3}=-6$

Therefore: $(x,y)=(6\sqrt{3}, -6)$

The vector in the form ai+bj is therefore:

$6\sqrt{3}i-6j$

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3 years ago

ZA and ZB are vertical angles. If m A = (8x – 20)° and m B = (3x – 5)º,

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Answer:

x=11

Step-by-step explanation:

Vertical angles are congruent, so m∠A = m∠B.

4x+8 = 5x-3

Subtract 5x from both sides.

-1x+8=-3

Subtract 8 from both sides to isolate the variable.

-1x=-11

Divide both sides by -1 to solve for x.

x=11

Plug in 11 for x into m∠A=(4x+8)=(4(11)+8)=(44+8)=52.

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Answer:

the correct answer is 5 snowmen

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262 + 923 + 231 - 138 = ?​

262 + 923 + 231 - 138 = ?