C = 15x + 50
let c be $125 since c represents the cost
15x + 50 = 125
15x = 125 - 50
15x = $75
x = 75 ÷ 15
x = 5
Answer:
6 titles and 16 acts were elaborated
Step-by-step explanation:
Let the number of titles be t and the number of acts be a
Since the total is 22 operations:
a + t = 22 •••••••(i)
Total amount from titles = 3500 * t = 3500t
Total amount from acts = 2000 * a = 2000a
2000a + 3500t = 53,000 ••••••(ii)
From i, a = 22-t
Insert this in ii
2000(22-t) + 3500t = 53,000
44,000 - 2000t + 3500t = 53,000
1,500t = 53000-44000
1500t = 9000
t = 9000/1500
t = 6
But a = 22 -
= 22-6 = 16
Id say B, y=-2/3+3
Hope this helps
Answer:
Gila Monster is 1.54 times that of Chuckwalla.
Step-by-step explanation:
Given:
Average Length of Gila Monster = 0.608 m
Average Length of Chuckwalla = 0.395 m
We need to find the number of times the Gila monster is as the Chuckwalla.
Solution:
Now we know that;
To find the number of times the Gila monster is as the Chuckwalla we will divide the Average Length of Gila Monster by Average Length of Chuckwalla.
framing in equation form we get;
number of times the Gila monster is as the Chuckwalla = 
Rounding to nearest hundredth's we get;
number of times the Gila monster is as the Chuckwalla = 1.54
Hence Gila Monster is 1.54 times that of Chuckwalla.