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lana66690 [7]
3 years ago
5

How do I find x? It’s for a riddle

Mathematics
1 answer:
Hunter-Best [27]3 years ago
6 0

Answer:

106

Step-by-step explanation:

174-68=106

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The cost of going to the big playland park for a family is given by c = 15x + 50, where c represents the cost and x represents t
marusya05 [52]
C = 15x + 50

let c be $125 since c represents the cost
15x + 50 = 125
15x = 125 - 50
15x = $75
x = 75 ÷ 15
x = 5
3 0
3 years ago
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A notary receives $ 3500 for elaborating a title property and $2000 for the constitutive act of an enterprise. In a month did a
Andrew [12]

Answer:

6 titles and 16 acts were elaborated

Step-by-step explanation:

Let the number of titles be t and the number of acts be a

Since the total is 22 operations:

a + t = 22 •••••••(i)

Total amount from titles = 3500 * t = 3500t

Total amount from acts = 2000 * a = 2000a

2000a + 3500t = 53,000 ••••••(ii)

From i, a = 22-t

Insert this in ii

2000(22-t) + 3500t = 53,000

44,000 - 2000t + 3500t = 53,000

1,500t = 53000-44000

1500t = 9000

t = 9000/1500

t = 6

But a = 22 -

= 22-6 = 16

5 0
3 years ago
If Asher plays each of the remaining seasons for which he is eligible, what is the average number of doubles he needs to hit per
PtichkaEL [24]

Answer:

the

Step-by-step explanation:

6 0
3 years ago
Which is the equation of a line that has a slope of mc005-1.jpg and passes through point (2, –3
goldenfox [79]
Id say B, y=-2/3+3
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8 0
3 years ago
The two largest lizards in the united states are the gila monster and the chuckwalla. The average gila monster is 0.608 meter lo
Mamont248 [21]

Answer:

Gila Monster is 1.54 times that of Chuckwalla.

Step-by-step explanation:

Given:

Average Length of Gila Monster = 0.608 m

Average Length of Chuckwalla = 0.395 m

We need to find the number of times the Gila monster is as the Chuckwalla.

Solution:

Now we know that;

To find the number of times the Gila monster is as the Chuckwalla we will divide the Average Length of Gila Monster by Average Length of Chuckwalla.

framing in equation form we get;

number of times the Gila monster is as the Chuckwalla = \frac{0.608}{0.395} = 1.5392

Rounding to nearest hundredth's we get;

number of times the Gila monster is as the Chuckwalla = 1.54

Hence Gila Monster is 1.54 times that of Chuckwalla.

5 0
3 years ago
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