Answer:
A) x^2 + 2x+ y^2 - 4y + z^2 - 2z - 63 = 0
B) radius = 5
center = (4,-1,-3)
Step-by-step explanation:
A ) Determine the curve in which the sphere intersects the yz-plane
determine the radius ( r ) = √((6-(-1))2+(-2-2)2+(3-1)2) = √69
next the equation of the sphere ( curve in which the sphere intersects the yz-plane )
x^2+2x+y^2-4y+z^2-2z-63 = 0
B) determine the center and radius of the sphere
X^2 + y^2 + z^2 -8x + 2y +6z + 1 = 0
(x-4)2+(y+1)2+(z+3)2 = 25 = 52
radius = 5
center = (4,-1,-3)
Answer:
8 units
Step-by-step explanation:
so there is something called Pythagorean thereon and it states that a^2+b^2=c^2
and 6 is either a or b
and c is ten so
6^2+b^2=10^2
36+b^2=100
b^2=64
here you need to find the square root in order to delete the power so
b=8
or
x=8