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lions [1.4K]
3 years ago
12

Find an equation of the sphere that passes through the point (6, -2, 3) and has center (-1, 2, 1). Find the curve in which the s

phere intersects the yz-plane. Find the center and radius of the sphere
X^2 + y^2 + z^2 -8x + 2y +6z + 1 = 0
Mathematics
1 answer:
svet-max [94.6K]3 years ago
5 0

Answer:

A)  x^2 + 2x+ y^2 - 4y + z^2 - 2z - 63 = 0

B) radius = 5

center  = (4,-1,-3)

Step-by-step explanation:

x^2 + y^2 + z^2 - 8x + 2y + 6z + 1 = 0

A ) Determine the curve in which the sphere intersects the yz-plane

determine the radius ( r ) =  √((6-(-1))2+(-2-2)2+(3-1)2) = √69

next the equation of the sphere ( curve in which the sphere intersects the yz-plane )

x^2+2x+y^2-4y+z^2-2z-63 = 0

B) determine the center and radius of the sphere

X^2 + y^2 + z^2 -8x + 2y +6z + 1 = 0

(x-4)2+(y+1)2+(z+3)2 = 25 = 52

radius = 5

center  = (4,-1,-3)

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Find the length of the diagonal AD in the pentagon ABCDE shown in the coordinate plane.
Xelga [282]

Answer:

\sqrt{73} units.

Therefore, Option C is correct.

Step-by-step explanation:

We have given a pentagon ABCDE

We need to calculate its length

That means we have to find the distance of AD

So, coordinates of A(1,6) and D(4,-2)

Using distance formula:

\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Here,x_1=1,y_1=6,x_2=4,y_2=-2

On substituting the values we will get:

\sqrt{(4-1)^2+(-2-6)^2}

On simplification:

\sqrt{3^2+(-8)^2}

\sqrt{9+64}

\sqrt{73}.

Hence, the length of AD is  \sqrt{73} units.

Therefore, Option C is correct.

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3 years ago
Evaluate this expression. 5^-3
sweet-ann [11.9K]

Answer:

\Huge \boxed{\frac{1}{125}}

Step-by-step explanation:

<h2>Order of operations</h2>

PEMDAS

Parenthesis, exponent, multiply, divide, add, and subtract from left to right.

Do exponent.

\displaystyle \frac{1}{5^3}

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\displaystyle \frac{1}{125}=125

\large \boxed{\frac{1}{125}}, which is our answer.

Hope this helps!

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