All categories

3 years ago

HELP ASAP! BEING TIMED!

Mathematics

2 answers:

Sloan [31]3 years ago

6 0

Answer:

Step-by-step explanation:

that what i thank it is

pantera1 [17]3 years ago

4 0

From seeing the image and looking at it for a while I would think five please do not hate on me if I’m incorrect

You might be interested in

What is the value of 9a + 6b?

Svetlanka [38]

i) 3a+2b=9 /*3

9a+6b=27

ii) 8x+6y=60 /: 2

4x+3y=30

6 0

3 years ago

Read 2 more answers

What are the ordered pairs of the solutions for the<br> following system of equations?

Lorico [155]

Answer:

(3,1);(6,-2)

Step-by-step explanation:

I pretty much just looked at where they both intersected with each other and you'll get your answer.

3 0

3 years ago

What is 3.9 divided by 100.000

Amanda [17]

Answer: 0.039

Step-by-step explanation: you move the "3.9" 2 decimal places to the right. If you did the inverse (multiplying by 100) you would get 390.00

3 0

2 years ago

Instructions: Find the angle measures given the figure is a rhombus.<br> Please Help!

nataly862011 [7]

Answer:

Step-by-step explanation:

since this is rhombus 1 2 3 4 must be equal

|NP|=|MN|

so 180-120=60

60/2=30

7 0

2 years ago

Read 2 more answers

Assume we need to estimate the mean of a normally-distributed population with great accuracy. Specifically, for significance lev

bulgar [2K]

Answer:

$n = 2662.56\sigma^2$

Step-by-step explanation:

We are given the following in the question:

Significance level = 0.01

Width of interval = 0.1

Population variance = $\sigma^2$

We have to find the sample size so that the width of the confidence interval is no larger than 0.1

$z_{critical}\text{ at}~\alpha_{0.01} = \pm 2.58$

Formula for sample size:

$n = \displaystyle\frac{z^2\sigma^2}{E^2}$

where E is the margin of error. Since the confidence interval width is 0.1,

$E = 0.05$

Putting these values in the equation:

$n = \displaystyle\frac{(2.58)^2\sigma^2}{(0.05)^2} = 2662.56\sigma^2$

So, the above expression helps us to calculate the sample size so that the width of the confidence interval is no larger than 0.1 for different sample variances.

4 0

3 years ago