Answer:
for the first one x=4 and y=2
Answer:
Option A - ![a_0= 2,a_1= 3,a_2= 5,a_3= 9](https://tex.z-dn.net/?f=a_0%3D%202%2Ca_1%3D%203%2Ca_2%3D%205%2Ca_3%3D%209)
Step-by-step explanation:
Given : For the sequence ![a_n= 2^n + 1](https://tex.z-dn.net/?f=a_n%3D%202%5En%20%2B%201)
To find : Identify the values of following?
Solution :
The nth term of the sequence is ![a_n= 2^n + 1](https://tex.z-dn.net/?f=a_n%3D%202%5En%20%2B%201)
Substitute n=0,1,2 and 3
When n=0,
![a_0= 2^0+ 1](https://tex.z-dn.net/?f=a_0%3D%202%5E0%2B%201)
![a_0= 1+1](https://tex.z-dn.net/?f=a_0%3D%201%2B1)
![a_0=2](https://tex.z-dn.net/?f=a_0%3D2)
When n=1,
![a_1= 2^1+ 1](https://tex.z-dn.net/?f=a_1%3D%202%5E1%2B%201)
![a_1= 2+1](https://tex.z-dn.net/?f=a_1%3D%202%2B1)
![a_1=3](https://tex.z-dn.net/?f=a_1%3D3)
When n=2,
![a_2= 2^2+ 1](https://tex.z-dn.net/?f=a_2%3D%202%5E2%2B%201)
![a_2=4+1](https://tex.z-dn.net/?f=a_2%3D4%2B1)
![a_2=5](https://tex.z-dn.net/?f=a_2%3D5)
When n=3,
![a_3= 2^3+ 1](https://tex.z-dn.net/?f=a_3%3D%202%5E3%2B%201)
![a_3= 8+ 1](https://tex.z-dn.net/?f=a_3%3D%208%2B%201)
![a_3= 9](https://tex.z-dn.net/?f=a_3%3D%209)
Therefore, The value is ![a_0= 2,a_1= 3,a_2= 5,a_3= 9](https://tex.z-dn.net/?f=a_0%3D%202%2Ca_1%3D%203%2Ca_2%3D%205%2Ca_3%3D%209)
So, Option A is correct.
Answer:
<h3>11 teams having equal 9 members.</h3><h3>The number of members in a team is 9</h3>
Step-by-step explanation:
Given a club has 54 male members and 45 female members. Also given that the club is having a contest, and there must be are all male and all female in teams competing the contest.
<h3>To find the most members a team ca have :</h3>
Male =54 members and Female =45 members
Total number of members = male members + female members
=54+45
=99
∴ Total number of members=99
∴ The number of members in a team is 9.
From the given problem the teams must all be equal, and each and every member should be on a team.
<h3>Hence 11 teams equals 9 members</h3>
Answer:
2.61
Step-by-step explanation:
Answer: a. 90°
Step-by-step explanation:
We know that the in a circle, the measure of an inscribed angle is half the measure of the central angle with the same intercepted arc.
In the problem∠XYZ is the inscribed angle
∠XYZ=![\frac{1}{2}\ arc(XZ)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5C%20arc%28XZ%29)
⇒ ∠XYZ=![\frac{1}{2}\angle{XZ}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Cangle%7BXZ%7D)
Since XZ is a diameter of the circle which is a line segment, thus ∠XZ=180°
∴ ∠XYZ=![\frac{1}{2}180^{\circ}=90^{\circ}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D180%5E%7B%5Ccirc%7D%3D90%5E%7B%5Ccirc%7D)
∴ ∠XYZ=![90^{\circ}](https://tex.z-dn.net/?f=90%5E%7B%5Ccirc%7D)
Therefore, a. 90° is the measure of ∠XYZ.