The correct answer among all the other choices is A. upper quartile. This is the term that refers to the median of the upper half of all the data. Thank you for posting your question. I hope that this answer helped you. Let me know if you need more help.
If my calculations are correct, Colton swam 288 yards. Really hope this helps.
General idea:
When we factor a trinomial of the form
, we need two numbers m and n to write it as product of two binomials like
, where
.
In order to get two numbers we need to list the factor pairs of c and see which two factors add up to give b.
Applying the concept:
![\frac{x^2-10x+14}{x-8}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%5E2-10x%2B14%7D%7Bx-8%7D%20%20)
We need to make alterations to the constant term in such a way that below equation is true.
![x^2-10x+c=(x-8)(x+n)\\ \\ Comparing \; x^2+bx+c=(x+m)(x+n) \; with \; above \; equation \;,\\\\ We\; get\; m = -8\; and \; b = -10\\\\ Also \; we \; know, \; m + n = b \; \; and \;\; m \cdot n= c\\ \\ -8+n=-10 \; \ [ Adding \; 8 \; on \; both \; sides]\\ \\ -8+n+8=-10+8 \; [Combining \; like \; terms \; on \; either \; side]\\ \\ n=-2 \\ \\ c=m \cdot n = -8 \cdot -2 = 16](https://tex.z-dn.net/?f=%20x%5E2-10x%2Bc%3D%28x-8%29%28x%2Bn%29%5C%5C%20%5C%5C%20Comparing%20%5C%3B%20x%5E2%2Bbx%2Bc%3D%28x%2Bm%29%28x%2Bn%29%20%5C%3B%20with%20%5C%3B%20above%20%5C%3B%20equation%20%5C%3B%2C%5C%5C%5C%5C%20We%5C%3B%20get%5C%3B%20m%20%3D%20-8%5C%3B%20and%20%5C%3B%20b%20%3D%20-10%5C%5C%5C%5C%20Also%20%5C%3B%20we%20%5C%3B%20know%2C%20%5C%3B%20m%20%2B%20n%20%3D%20b%20%5C%3B%20%5C%3B%20and%20%5C%3B%5C%3B%20m%20%5Ccdot%20n%3D%20c%5C%5C%20%5C%5C%20-8%2Bn%3D-10%20%5C%3B%20%5C%20%5B%20Adding%20%5C%3B%208%20%5C%3B%20on%20%5C%3B%20both%20%5C%3B%20sides%5D%5C%5C%20%5C%5C%20%20-8%2Bn%2B8%3D-10%2B8%20%5C%3B%20%5BCombining%20%5C%3B%20like%20%5C%3B%20terms%20%5C%3B%20on%20%5C%3B%20either%20%5C%3B%20side%5D%5C%5C%20%5C%5C%20n%3D-2%20%5C%5C%20%20%20%20%5C%5C%20c%3Dm%20%5Ccdot%20n%20%3D%20-8%20%5Ccdot%20-2%20%3D%2016%20)
Conclusion:
Right now the numerator is
, we need to <em><u>add 2</u></em> to the constant of the numerator expression to get
.
For the numerator to have (x-8)
as a factor, its constant term must be <em><u>16 </u></em>.
I think it would be 17%
hope this helps,
QueenofLovers123