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Wittaler [7]
3 years ago
8

A florist wants to determine if a new additive would extend the life of cut flowers longer than the original additive. The flori

st randomly selects 20 carnations from the ones recently delivered by the greenhouse and places the first 10 in water with the new additive and remaining 10 in water with the original additive. After three weeks, 6 carnations placed in the new additive still looked healthy and 2 carnations placed in the original additive still looked healthy. The proportion of healthy carnations with the new additive was significantly greater than the proportion of healthy carnations with the original additive.
Which of the following is a valid conclusion?

Conclusions about cause and effect for the additives can be made, because the florist randomly selected the 20 carnations; additionally, inferences can be made about the population of carnations at the greenhouse.
Conclusions about cause and effect for the additives cannot be made, because the florist did not randomly assign the 20 carnations; however, inferences can be made about the population of carnations at the greenhouse, because the sample was random.
Conclusions about cause and effect for the additives can be made, because the florist took a random sample of 20 carnations; however, inferences cannot be made about the population of carnations at the greenhouse, because the carnations were not randomly assigned to the treatments.
Conclusions about cause and effect for the additives cannot be made, because the florist took a random sample of 20 carnations; and, inferences cannot be made about the population of carnations at the greenhouse, because the carnations were not randomly assigned to the treatments.
Mathematics
1 answer:
bekas [8.4K]3 years ago
7 0

Answer:

The last one would be a valid conclusion {Conclusions about cause and effect for the additives cannot be made, because the florist took a random sample of 20 carnations; and, inferences cannot be made about the population of carnations at the greenhouse, because the carnations were not randomly assigned to the treatments.}

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In the past decades there have been intensive antismoking campaigns sponsored by both federal and private agencies. In one study
DIA [1.3K]

Answer:

z=\frac{0.384-0.362}{\sqrt{0.374(1-0.374)(\frac{1}{4276}+\frac{1}{3908})}}=2.055    

The p value can be calculated from the alternative hypothesis with this probability:

p_v =2*P(Z>2.055)=0.0399    

And the best option for this case would be:

C. between 0.01 and 0.05.

Step-by-step explanation:

Information provided

X_{1}=1642 represent the number of smokers from the sample in 1995

X_{2}=1415 represent the number of smokers from the sample in 2010

n_{1}=4276 sample from 1995

n_{2}=3908 sample from 2010  

p_{1}=\frac{1642}{4276}=0.384 represent the proportion of smokers from the sample in 1995

p_{2}=\frac{1415}{3908}=0.362 represent the proportion of smokers from the sample in 2010

\hat p represent the pooled estimate of p

z would represent the statistic    

p_v represent the value for the pvalue

System of hypothesis

We want to test the equality of the proportion of smokers and the system of hypothesis are:    

Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}    

The statistic is given by:

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{1642+1415}{4276+3908}=0.374  

Replacing the info given we got:

z=\frac{0.384-0.362}{\sqrt{0.374(1-0.374)(\frac{1}{4276}+\frac{1}{3908})}}=2.055    

The p value can be calculated from the alternative hypothesis with this probability:

p_v =2*P(Z>2.055)=0.0399    

And the best option for this case would be:

C. between 0.01 and 0.05.

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bonufazy [111]

Answer:

All statements are correct for two congruent triangles

Step-by-step explanation:

If two triangles are congruent than the rules states that

Triangles are congruent when all corresponding sides and interior angles are congruent. The triangles will have the same shape and size, but one may be a mirror image of the other.

As the fig shows two triangle

Δ PQR

Δ LMN

All three corresponding sides of triangle are congruent

all three corresponding  angles are congruent

Both triangle are of same size

Both are of same shape

hence all the statements are CORRECT

Keywords:Geometry

Learn more about Geometry at:

  • mathopenref.com/congruenttriangles.html
  • brainly.com/question/3617539

#learnwithBrainly

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Area of base

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So possible dimensions are optionB given

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Verified

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Remember: higher risk means you wait less time to get more money.
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