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MaRussiya [10]
3 years ago
13

The amount of time (t) in minutes it takes Jeff to mow an average sized yard is related to (n) the number of yards he mows. The

equation is t = 2n + 12. How many lawns does Jeff mow if it takes him 30 minutes?
Mathematics
1 answer:
Sveta_85 [38]3 years ago
4 0

Answer:

Jeff mows 9 yards of lawn in 30 minutes

Step-by-step explanation:

The equation that models the amount of time (t) in minutes it takes Jeff to mow an average sized yard is t=2n+12, where n is the number of yards he mows.

To find the number of yards Jeff mows in 30 minutes, we set the equation to 30 and solve for n.

\implies 2n+12=30

Add -12 to both sides:

\implies 2n=30-12

\implies 2n=18

Divide both sides by 2

\implies \frac{2n}{2}=\frac{18}{2}

\implies n=9

Hence Jeff mows 9 yards of lawn in 30 minutes.

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WILL GIVE BRAINIEST As a fundraiser the school has a pie eating contest. Matt eats 2.75 pies in 300 seconds. If Matt eats at a c
romanna [79]

Answer:

0.01

Step-by-step explanation:

300 seconds = 2.75 pies

1 second = (1/300) × 2.75

= 0.009167

Approximately, 0.01 pie

5 0
2 years ago
a national survey conducted among a simple random sample of 1,507 adults shows that 56% of americans think the civil war is stil
soldier1979 [14.2K]

a)

z=4.658\\p_v=P(z > 4.65)=1-P(z < 4.65)=1.581x*10^{-6}

b) By assuming a significance level of α = 0.05 and observing that p_v > α, we can reject the null hypothesis at this level of significance. And in this instance, it makes sense that more than 50% of Americans believe that the Civil War still has an impact on American politics and political life.

c) The confidence interval at 90% would be shown (0.527;0.593).

About 54% to 59% of all Americans, in our opinion, believe that the Civil War is still significant today.

<h3>What is a survey?</h3>

A survey is a set of questions used in human subject research with the goal of gathering specific information from a certain population. Surveys can be carried out via the phone, by mail, online, at street corners, and even in shopping centers.

a)

1) The presented data and the notation "n=1507" refer to the random sample of Americans, "X" denoting the proportion of those Americans in the sample who believe that the Civil War is still significant to American politics and political life, and "p cap" denoting the estimated number of those Americans.

Since the problem specifies that majority  α=0.05 represents the significance threshold, p_0 is the number that we wish to test (no given, but is assumed)

Z would stand for the statistic (interesting variable), and p_v for the p value (variable of interest)

P is the percentage of the public that believes that the Civil War still has an impact on American politics and political life.

2) Useful concepts and formulas

The allegation that more Americans than 50% believe the Civil War is still significant to American politics and political life needs to be tested through a hypothesis (Majority). :

Alternative Hypothesis: p\geq 0.5

Null Hypothesis: p\leq 0.5

The proportion is thought to have a normal distribution.

This test for the percentage of union membership has one tail higher.

Verify whether the sample conforms to the presumptions required for the test to be applied.

a) The random sample must be representative; in this situation, there is no mention of this issue, but it is safe to presume that it exists.

b) The sample size must be sufficient.

np_0=1507*0.5=753.5 > 10\\n(1-p_0)=1507*(1-0.5)=753.5 > 10

3. Determine the statistic.

The formula used to calculate the statistic is as follows:

z=\frac{p-p_0}{\sqrt{\frac{p_0(1-p_0)}{n} } }= \frac{0.56-0.5}{\sqrt{\frac{0.5(1-0.5)}{1507} } }=4.658

P value= p_v=P(z > 4.65)=1-P(z < 4.65)=1.581*x*10^{-6}

According to the alternative hypothesis, the following would be the p value:

P value= p_v=P(z > 4.65)=1-P(z < 4.65)=1.581*x*10^{-6}

Using this formula, the confidence interval would be determined.

p ± z_{\frac{\alpha }{2}}\sqrt{\frac{p(1-p)}{n} }

With the value of \alpha and \alpha _2, we can get the quantile necessary for the interval in the normal standard distribution for the 90% confidence interval.

z_{\frac{\alpha }{2} }=2.58

adding the following to the formula for the confidence interval:

0.56-2.58\sqrt{\frac{0.56(1-0.56)}{1507} } = 0.527\\0.56+2.58\sqrt{\frac{0.56(1-0.56)}{1507} } = 0.593

Also provided would be the 90% confidence interval (0.527;0.593).

About 54% to 59% of all Americans, in our opinion, believe that the Civil War is still significant today.

And because the interval does not contain the value of 0.5, we can conclude that, at a 90% level of confidence, the percentage of Americans who believe that the Civil War is still relevant to American politics and political life is higher than 0.5. This result is consistent with the result of part b.

To know more about survey, visit:

brainly.com/question/13192080

#SPJ4

6 0
2 years ago
Jessie estiments the weight of her cat to be 10 pounds the actual weight of the cat is 13.75 pounds fine the percent error
GarryVolchara [31]

Answer:

The percent error would be 27.27%

Step-by-step explanation:

percent error = \frac{measured - actual}{actual} x 100%


3 0
4 years ago
A deli sells 2 hot dogs for $2.50. What is the constant of proportionality of dollars per hot dog?
attashe74 [19]

Answer:

$1.25 per hot dog

Step-by-step explanation:

6 0
3 years ago
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I need help solving
zhenek [66]
Super blurry can you resubmit or type out the question
7 0
3 years ago
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