speed of current is 1.5 mi/hr
Answer:
let the rate in still water be x and rate of the current be y.
speed down the river is:
speed=distance/time
speed=14/2=7 mi/h
speed up the river is:
speed=(14)/(3.5)=4 mi/hr
thus total speed downstream and upstream will be:
x+y=7...i
x-y=4.......ii
adding the above equations i and ii we get:
2x=11
x=5.5 mi/hr
thus
y=5-5.5=1.5 mi/r
thus the speed in still waters is 5.5 mi/hr
speed of current is 1.5 mi/hr
Answer:
f'(1) = 2
Step-by-step explanation:
f(x) = 2x^2 -2x +3
Take the derivative
f'(x) = 2 * 2x - 2 * 1
f'(x) = 4x -2
f'(1) = 4(1) -2
=4-2
=2
(3,452 * 2) = round trip = 6,904.
6,904 * 3 = total distance = 20,712.
Therefore, the final answer is 20,712 miles.
You need to factor the numerator and denominator...
(2x^2+4x-2x-4)/(2x^2-2x-2x+2)
(2x(x+2)-2(x+2))/(2x(x-1)-2(x-1))
((2x-2)(x+2))/((2x-2)(x-1)) so the (2x-2)s cancel out leaving
(x+2)/(x-1)
Omg u can’t even figure out this? Why are you still going school