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4 years ago

10

what is the degree of the polynomial ? what is the leading coefficient ? describe the end behavior of each function. f(x)=x^4-2x

^2+2

1 answer:

Verizon [17]4 years ago

3 0

Answer:

4th degree polynomial with leading coefficient of 1.

As x goes to negative or positive infinity, y goes to positive infinity in both cases.

Step-by-step explanation:

The degree of a polynomial is the highest exponent on the variable. Here it is 4.

The leading coefficient is the coefficient on the the term with the highest degree, Here there is none so it is 1.

The end behavior is how x and y behave at negative and positive infinity. When graphed, this equation has a W shape. This means at each end y goes to positive infinity.

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I dont know how to do this, please help.

Anit [1.1K]

I'm assuming this is what they want? haha

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4 years ago

Read 2 more answers

Solve for ddd. 6d-\dfrac{11}2=2d-\dfrac{13}26d− 2 11 =2d− 2 13 6, d, minus, start fraction, 11, divided by, 2, end fraction,

ANEK [815]

Answer:

$d = -\dfrac{1}{4}$

Step-by-step explanation:

Given

$6d-\dfrac{11}2=2d-\dfrac{13}{2}$

Required

Solve for d

$6d-\dfrac{11}2=2d-\dfrac{13}{2}$

Collect Like Terms

$-2d + 6d=-\dfrac{13}{2}+\dfrac{11}{2}$

$4d=-\dfrac{13}{2}+\dfrac{11}{2}$

Take LCM

$4d=\dfrac{-13+11}{2}$

$4d=\dfrac{-2}{2}$

$4d = -1$

Make d the subject

$d = -\dfrac{1}{4}$

5 0

3 years ago

Pllllllzzzzzzzzz help me

Fed [463]

Answer:

for the first one he will get $51

the second one is £2.70

Step-by-step explanation:

8 0

3 years ago

Two cars are traveling down the highway with the same speed. If the first car increases its speed by 1km/hr, and the other car d

Olegator [25]

Answer:

The speed of the cars is $32 \frac{km}{h}$

Step-by-step explanation:

First we must first have the clear concept that $speed=\frac{distance}{time}$ or $s=\frac{d}{t}$

Our question is the speed of the cars then the variable to clear will be s.

Let's raise the equation for each car taking into account that we have the following data:

Car 1: $s_{1}=s+1$ , $t_{1}=2$ and $d_{1}= d_{2}$

Car 1: $s_{2}=s-10$ , $t_{2}=3$ and $d_{1}= d_{2}$

The two cars travel the same distance so we will raise the distance formula for each car and then match them.

<em>Car 1</em>

$d_{1}=s_{1}*t_{1}$

$d_{1}=(s+1)*2$

$d_{1}=2s+2$

<em>Car 2</em>

$d_{2}=s_{2}*t_{2}$

$d_{2}=(s-10)*3$

$d_{2}=3s.30$

$d_{1}=d_{2}$

$2s+2=3s-30$

$2+30=3s-2s$

$32=s$

The speed of the cars is 32 km/hr

7 0

4 years ago

A bicycle store costs $4000 per month to operate. The store pays an average of $75 per bike. The average selling price of each

Montano1993 [528]

Answer:

50 you need to break even

Step-by-step explanation:

4000+75n= stores operating costs

155N=stores profit

155n=4000+75n

-75 -75

80n=4000

80/80 4000/80

N=50

6 0

4 years ago