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Mars2501 [29]
2 years ago
8

IF

Mathematics
1 answer:
Montano1993 [528]2 years ago
5 0

Answer:

commutative property

Step-by-step explanation:

commutative property

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A survey of UF students asked for their employment status and their year in school. The results appear below.
cestrela7 [59]

Answer:

There is no relationship between your year in school and having a job.

Step-by-step explanation:

In this instance, the chi sq test need to be performed.

Chi sq is used to determine if there is a significant relationship between two categorical variables.

The two variables here are year in school and employment status.

The two variables are independent(no relationship exists)

This implies that there is null hypothesis

Therefore, the Null Hypothesis is

There is no relationship between your year in school and having a job.

3 0
3 years ago
What is the phase shift of the graph of y=−sin(x+π/4)+2
butalik [34]

Answer:

π/4

Step-by-step explanation:

x is the variable

-1 inverts the curve

π/4 is the phase shift or x axis offset

2 is the y axis offset

5 0
3 years ago
Which of the following expressions is equivalent to the expression a^2/3
vladimir1956 [14]

∛a² → C

From the ' law of exponents '

a^{\frac{m}{n} } = \sqrt[n]{a^{m} }


3 0
3 years ago
What is 8 + x ≥ 12 on a number line???
levacccp [35]
8+x ≥ 12
-8 -8
x ≥ 4
(i tried taking the picture)

6 0
2 years ago
Help I am very bad at math I need answers by tomorrow if you can help please do​
d1i1m1o1n [39]

Answer:

Step-by-step explanation:

(a - b)(a +b) = a² - b²

1 - Sin² A = Cos² A

LHS = \frac{1}{1- Sin A} + \frac{1}{1 + Sin A}\\\\= \frac{1*(1 + Sin A)}{(1- Sin A)(1 + Sin A)} + \frac{1*(1- Sin A)}{(1 + Sin A)(1- Sin A)}\\\\= \frac{1 + Sin A+ 1 - Sin A}{1^{2}-  Sin^{2} A}\\\\= \frac{2}{1 - Sin^{2} A}\\\\= \frac{2}{Cos^{2} A}\\\\= 2 Sec^{2} A

2)  Sec² A - Tan² A = 1

LHS = \frac{1}{Sec A - Tan A}\\\\=\frac{1*(Sec A + Tan A)}{(Sec A -  Tan A)(Sec A + Tan A)}\\\\=\frac{Sec A + Tan A}{Sec^{2} A - Tan^{2} A}\\\\=\frac{Sec A + Tan A }{1}\\\\= Sec A + Tan A = RHS\\\\\\

3) LHS  = Cosec² A + Cot² A

             = Cosec² A +  Cosec² A - 1

            = 2Cosec² A - 1   = RHS

4) LHS = \frac{Sec A}{Cos A}- \frac{Tan A}{Cot A}\\\\          = Sec A*\frac{1}{Cos A}-Tan A*\frac{1}{Cot A}\\\\ = Sec A * Sec A - Tan A * Tan A\\\\= Sec^{2} A - Tan^{2} A \\\\= 1

3 0
3 years ago
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