All categories

3 years ago

What is t'(x) when t(x) = In x2 2x2+3x+2 ?

Mathematics

1 answer:

Korvikt [17]3 years ago

7 0

Step-by-step explanation:

2-×^2

t(×)=3×

(s o t )(x)=st(×)=s(t(x))=2-(3×)^2=2-9x^2

(s o t)(-7) =2-9(-7)^2=2-9(49)= 2-441= -439

You might be interested in

Solve for z.<br> 7z +4 – 9z = 8<br> z = [?]

ZanzabumX [31]

Answer:

Z = -2

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

25 points!!!! HELP ANSWER!

Fantom [35]

Answer:

a) 1st and 2nd

b) 4th one

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Adult entrance fees to amusement parks in the United States are normally distributed with a population standard deviation of 2.5

kondor19780726 [428]

Answer: 1.509

Step-by-step explanation:

The formula of Margin of Error for (n<30):-

$E=t_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

Given : Sample size : n= 22

Level of confidence = 0.99

Significance level : $\alpha=1-0.99=0.01$

Using the t-distribution table ,

Critical value : $t_{n-1, \alpha/2}=t_{21,0.005}= 2.831$

Standard deviation: $\sigma=\text{ 2.5 dollars }$

Then, we have

$E=( 2.831)\dfrac{2.5}{\sqrt{22}}\approx1.509$

Hence, the margin of error for a 99% confidence interval for the population mean =1.509

4 0

3 years ago

To be honest this is a dud question just answer for points and if multiple people answer I will give one of them brainliest.

MArishka [77]

Answer:

If you live to be 70, you will have spent 10 years of your life on Monday.

6 0

3 years ago

Show how to find the roots (zeros) of the function in the picture below.

Vikki [24]

Answer:

The roots (zeros) of the function are:

$x=5,\:x=-8$

Step-by-step explanation:

Given the function

$f\left(x\right)=x^2+3x-40$

substitute f(x) = 0 to determine the zeros of the function

$0=x^2+3x-40$

First break the expression x² + 3x - 40 into groups

x² + 3x - 40 = (x² - 5x) + (8x - 40)

Factor out x from x² - 5x: x(x - 5)

Factor out 8 from 8x - 40: 8(x - 5)

Thus, the expression becomes

$0=x\left(x-5\right)+8\left(x-5\right)$

switch the sides

$x\left(x-5\right)+8\left(x-5\right)=0$

Factor out common term x - 5

$(x - 5) (x + 8) = 0$

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

$x-5=0\quad \mathrm{or}\quad \:x+8=0$

Solve x - 5 = 0

x - 5 = 0

adding 5 to both sides

x - 5 + 5 = 0 + 5

x = 5

solve x + 8 = 0

x + 8 = 0

subtracting 8 from both sides

x + 8 - 8 = 0 - 8

x = -8

Therefore, the roots (zeros) of the function are:

$x=5,\:x=-8$

6 0

3 years ago