Answer:
Step-by-step explanation:
The distance from one score to another tends to increase, and a single score tends to provide a less accurate representation of the entire distribution.
Consider normal distribution it has increasing trend from -Inf to the mean. But has no probability at any point. But if you consider binomial distribution then you will get the information at any integer of its range, but not all values of real line. That is you will not have information on (0,1) so there you cannot comment for increment of that distribution.
Answer:
See below.
Step-by-step explanation:
First, notice that this is a composition of functions. For instance, let's let 
and 
. Then, the given equation is essentially 
. Thus, we can use the chain rule.
Recall the chain rule: ![\frac{d}{dx}[f(g(x))]=f'(g(x))\cdot g'(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%5Bf%28g%28x%29%29%5D%3Df%27%28g%28x%29%29%5Ccdot%20g%27%28x%29)
. So, let's find the derivative of each function:
We can use the Power Rule here:
Now:
Again, use the Power Rule and Sum Rule
Now, we can put them together:
Answer:
26
Step-by-step explanation:
When we subtract a negative it is like adding
(-16) - (-42)
(-16) + (42)
Re arranging the order
42 -16
26
She works for 40 hours, and then 5 hours.
So, for these first 40 hours, Tyra earns $21.40 per hour. We can find how much she earns in 40 hours:
21.40 x 40 = 856.
So, in the first 40 hours, she makes $856.
Now, for any number of hours Tayra works more that 40 hours, she will earn $32.10 each hour.
She works 5 hours over 40 hours, since it is 45 hours in total.
Hence, Tayra will earn $32.10 every hour for the 5 hours:
5 x 32.10 = 160.5.
Therefore, she will earn $160.50 for the 5 hours.
Now we have both of the earning amounts that make up how much she makes in the 45 hours. We can add them together
40 hours + 5 hours = 45 hours.
Substitute the amounts in the hours.
856 + 160.5 = 1016.5.
Thus, the answer is that Tyra will warn $1,016.50 in the total 45 hours.
Ergo, the correct answer is C.
Hope this helps, let me know if you need anything else! :)
