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Mashutka [201]
4 years ago
13

In which of the following intervals does the trigonometric inequality csc(x)> -sec(x) always hold true?

Mathematics
1 answer:
Kaylis [27]4 years ago
3 0
Answer:a is the answer
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Ben works for software company in Cleveland. To train new employees, Ben travels to their two other locations, Buffalo and Phila
Andru [333]

Answer:

Explanation:we will solve this question with help of linear programming.

Now,  let Ben goes x times in buffalo trip and goes y times in Philadelphia trip. Thus, according to the question, Min Z= 180x+300y

And s.t.r. 2x+3y≤105, where x≥5, y≥15.

since at (0,0) 0≤105(true), so area of 2x+3y≤105 will cover the origin.

But, 0≥5 and 0≥15 are false, so their area will not cover the origin.

Thus, after drawing the graph of these three lines we will get a feasible reason of triangle ABC, where point A≡(5,31.667), B≡(5,15), and C≡(30,15)

Z at A- 180×5+300×31.667=10,400.1

at B-180×5+300×15=1350( which is minimum.)

at C- 180×30+300×15=5,850

Thus, Ben should go 5 times to buffalo trip and 15 times to Philadelphia to minimize his cost which is $1350.




3 0
4 years ago
Jamie invests $1,200 in an account that earns 3% interest. Assuming continuous compounding, how much is in his account after 7 y
goblinko [34]

Answer:

The amount in account after 7 years of investment is $1478.4

Step-by-step explanation:

Given as :

The principal invested in account by Jamie = p = $1200

The rate of interest = r = 3% compounded annually

The Time period of investment = t=  7 years

Let The Amount in Jamie account = $ A

<u>For continuous compounding</u>

Amount = Principal × e^{r \times time}

Or, A = p × e^{r \times time}

Or, A = $1200 × e^{0.03 \times 7}

Or, A = $1200 × 2.71^{0.03 \times 7}

Or, A = $1200 × 1.232

∴  A = $1478.4

So, The amount after continuous compounding = A = $1478.4

Hence , The amount in account after 7 years of investment is $1478.4    Answer

5 0
4 years ago
Consider the number 284,682
Law Incorporation [45]

Answer:

Hundred thousand's 200000

Ten thousand's = 80000

Thousand's = 4000

Hundreds = 600

Tens = 80

Ones = 2

This is the place value of 284682

Two hundred eighty-four thousand six hundred eighty-two

5 0
3 years ago
Read 2 more answers
A) Find the average rate of change of the area of a circle with respect to its radius r as r changes from 4 to each of the follo
Black_prince [1.1K]
Area = π x radius²
dA/dr = 2πr
Average rate of change = (rate of change at one instant + rate of change at other instant)/2
= (2πr₁ + 2πr₂)/2
= (r₁ + r₂)π
Ai) 9π
Aii) 8.5π
Aiii) 8.1π

B) Instantaneous change:
(dA/dr) at (r = 4) = 2π(4)
= 8π
7 0
3 years ago
Please help me figure this out ASAP
Karolina [17]
You can just use a calculator but it’s 65.23
8 0
3 years ago
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