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3 years ago

Please help. I need the answer asap

Mathematics

1 answer:

Ymorist [56]3 years ago

4 0

Do u still need the answer its been 2 weeks now!

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A rectangle has a length two times the width. Describe how you would find the

IRINA_888 [86]

Answer:

perimeter = 6w

area = 2w^2

Step-by-step explanation:

we can use the variable w for width, and 2w for length perimeter would be width + width + length + length, or 6w

area is width x length or 2w^2

4 0

2 years ago

Read 2 more answers

3. What is the hypothesis of the following conditional statement?

lys-0071 [83]

Answer:

A: Two angles form a right angle.

Step-by-step explanation:

took the test

3 0

2 years ago

Simplify. 8 · 3 · x 13x 24x 22x 48x

Elina [12.6K]

$8\cdot3\cdot x=(8\cdot3)x=24x$

7 0

3 years ago

Consider a diving board that is 10 feet above a pool. If the ladder is 5 feet away from the base of the diving board, approximat

OleMash [197]

Answer: 15 feet

Step-by-step explanation:

From the question, we are informed that a diving board is 10 feet above a pool. Since the ladder is 5 feet away from the base of the diving board, to calculate how tall is the ladder is, we subtract -5 from 10. This will be:

= 10 - (-5)

= 10 + 5

= 15 feet

The answer is option C.

5 0

3 years ago

A leprechaun places a magic penny under a girls pillow. The next night there are 2 magic pennies under her pillow. The following

kiruha [24]

Answer:

After 47 days she will have more than 90 trillion pennies.

Step-by-step explanation:

At the beginning there was 1 penny. At the second day the amount of pennies under the pillow became 2.

The amount of pennies doubled each day. So the series is,

$1,2,4,8,16,32,.....$

This series is in geometric progression.

As the pennies from each of the previous days are not being stored away until more pennies magically appear so the sum of series will be,

$S_n=\dfrac{a(r^n-1)}{r-1}$

where,

a = initial term = 1,

r = common ratio = 2,

As we have find the number of days that would elapse before she has a total of more than 90 trillion, so

$\Rightarrow 90\times 10^{12}\le \dfrac{1(2^n-1)}{2-1}$

$\Rightarrow 90\times 10^{12}\le \dfrac{2^n-1}{1}$

$\Rightarrow 90\times 10^{12}\le 2^n-1$

$\Rightarrow 2^n\ge 90\times 10^{12}+1$

$\Rightarrow \log 2^n\ge \log (90\times 10^{12}+1)$

$\Rightarrow n\times \log 2\ge \log (90\times 10^{12}+1)$

$\Rightarrow n \ge \dfrac{\log (90\times 10^{12}+1)}{\log 2}$

$\Rightarrow n \ge 46.4$

$\Rightarrow n\approx 47$

8 0

3 years ago