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lesya [120]
2 years ago
8

Please help. I need the answer asap

Mathematics
1 answer:
Ymorist [56]2 years ago
4 0
Do u still need the answer its been 2 weeks now!
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What is 3 to the power of 3
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Solve for y 2x+y=3 thank you.
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ASA i think

Step-by-step explanation:

because if you start anywhere on the triangle you start at an angle

5 0
3 years ago
Can someone please help with this trig question?
atroni [7]
First we must understand how to write a logarithmic function:

log_{b}a=x

In the equation above, b is the base, x is the exponent, and a is the answer. These same variables can be rearranged to be expressed as an exponential equation as followed:

b^x=a

Next, we need to understand basic logarithm rules.

1. When a value is raised to a power, we can move the exponent to the front of the logarithm. Example:

log(a^2) = 2log(a)

2. When two variables are multiplied together, we can add the logarithms of the individual variables together. Example:

log(ab) = log(a) + log(b)

3. When a variable is divided by another variable, we can subtract the logarithms of the individual variables. Example:

log(a/b) = log(a) - log(b)

Now we can use these rules to solve the problem.

log(r)=log( \sqrt[3]{ \frac{A^2B}{C} } )

We can rewrite the cube root as:

log(r) = log( (\frac{A^2B}{C})^ \frac{1}{3} )

Now we can move  the one-third to the front:

log(r) =  \frac{1}{3} log( \frac{A^2B}{C} )

Now we can split up the logarithm:

log(r) =  \frac{1}{3} (log(A^2)+log(B)-log(C))

Finally, we can move the exponent to the front of the log of A:

log(r) = \frac{1}{3} (2log(A)+log(B)-log(C))

Distribute the one-third to get the answer:

log(r) = \frac{2}{3} log(A) +  \frac{1}{3} log(B) -  \frac{1}{3} log(C)

The answer is (4).


3 0
3 years ago
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