Answer:

Step-by-step explanation:
The question is simple. All we have to do is divide
by
. The answer to that is
.
Answer:

Step-by-step explanation:
The picture of the question in the attached figure
we know that
In the right triangle of the figure
----> by SOH (opposite side divided by the hypotenuse)
using a calculator

Nxnxnxbbxnxndnnsnsn nsnsnsndnnsndnndndnsndnndndnndnd
Answer:
Step-by-step explanation:
As the statement is ‘‘if and only if’’ we need to prove two implications
is surjective implies there exists a function
such that
.- If there exists a function
such that
, then
is surjective
Let us start by the first implication.
Our hypothesis is that the function
is surjective. From this we know that for every
there exist, at least, one
such that
.
Now, define the sets
. Notice that the set
is the pre-image of the element
. Also, from the fact that
is a function we deduce that
, and because
the sets
are no empty.
From each set
choose only one element
, and notice that
.
So, we can define the function
as
. It is no difficult to conclude that
. With this we have that
, and the prove is complete.
Now, let us prove the second implication.
We have that there exists a function
such that
.
Take an element
, then
. Now, write
and notice that
. Also, with this we have that
.
So, for every element
we have found that an element
(recall that
) such that
, which is equivalent to the fact that
is surjective. Therefore, the prove is complete.