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lesya [120]
3 years ago
14

Twice the sum of 13 and x is not greater than 15

Mathematics
1 answer:
Kobotan [32]3 years ago
7 0

Answer:

x = 0

Step-by-step explanation:

This is saying that 2(13x) < 15

If you have 2[13(0)] < 15

It will come to 2(0) < 15

This equals 0 < 15 which is true therefore making the <u>x</u> value = <u>0</u>

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Can someone please help me with this too
Svetach [21]

Answer:

I have no idea but I suggest making the rule to round the output to the nearest tenth because all the numbers on there have a 9 at the end.

Hope I helped, if I'm right please give brainliest because I cant level up until I get 2 more ;(

<3 Enjoy,

    Dea

3 0
3 years ago
The parabola y=<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^{2}" align="absmiddle" class
oksano4ka [1.4K]
Y=(x-h)^2+k where (h,k) is the vertex

So, equation of new parabola is:

y=(x+1)^2+7
7 0
3 years ago
Four less than the quotient of a number and 3 is -10
ahrayia [7]

your answer would be -18

6 0
3 years ago
Read 2 more answers
D) What is the measure of ∠H? Explain. (1 point)<br><br>  
lukranit [14]

Answer:

105 degrees i think

Step-by-step explanation:

E=75

H=105

75+105=180

7 0
3 years ago
What is the result of isolating y^2 in the equation below (x-2)^2+y^2=64?
natta225 [31]

What is the result of isolating y^2 in the equation below (x-2)^2+y^2=64?

Solution:

We want to isolate y^{2} from the equation (x-2)^{2} +y^{2} =64

To isolate y^{2}, we must try to get y^{2} alone

So, We must subtract (x-2)^{2} from both sides

(x-2)^{2}-(x-2)^{2}  +y^{2} =64-(x-2)^{2}

0 +y^{2} =64-(x-2)^{2}

y^{2} =64-(x^{2}-4x+4)

Distributing '-' inside parenthesis

y^{2} =64-x^{2} +4x -4

y^{2} =60-x^{2} +4x

6 0
3 years ago
Read 2 more answers
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