Y=-2/1x ivigvyvitvtuyvsybsubeeuwub
She used two trapezoids.
She put one trapezoid on top and one on the bottom.
The shape she ends up making is a hexagon.
So, to find the solution to this problem, we will we using pretty much the same method we used in your previous question. First, let's find the area of the rectangle. The area of a rectangle is length x width. The length in this problem is 16 and the width is 3, and after multiplying these together, we have found 48 in^2 to be the area of the square. Next, we can find the area of the trapezoid. The area of a trapezoid is ((a+b)/2)h where a is the first base, b is the second base, and h is the height. In this problem, a=16, b=5, and h=10. So, all we have to do is plug these values into the area formula. ((16+5)/2)10 = (21/2)10 = 105. So, the area of the trapezoid is 105 in^2. Now after adding the two areas together (48in^2 and 105in^2), we have found the solution to be 153in^2. I hope this helped! :)
3/4-3=43 Thsts the answer hopes it help
Answer:
If a line is parallel to another line, the slopes of both lines are the same. So far the equation would be, y=7/6x+b. To find the value of b, you substitute the given point into the equation. -2=7/6(-1)+b, -2=-7/6+b, b=-5/6. So the equation of the line is y=7/6x-5/6.
:)
