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Alja [10]
3 years ago
10

PLS ANSWER FAST WILL GIVE BRAINLYEST TIMED TEST!!!!

Physics
1 answer:
MariettaO [177]3 years ago
4 0
Using a=f/m u get 100 bc 5/.05 =100m/s
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because it is stationary....and has the ability to hold things in it...in a kind of random motion

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What is the pressure inside such a balloon (in atm) if it starts out at sea level with a temperature of 12.8°C and rises to an a
tatiyna

Answer:

The final pressure inside the balloon will be P_2=0.0359\ atm.

Explanation:

Given initial temperature of the balloon is T_1=12.8\°C

And the final temperature of the balloon is T_2=-47.7\°C

Initially, the balloon is at atmospheric pressure P_1=1\ atm and volume be V_1

And the final pressure in the balloon is P_2 and the volume be V_2

Also, it is given in the question that the final volume became twenty-two times the original volume.

We can write V_2=22V_1

Now, using ideal gas equation.

\frac{P_2V_2}{P_1V_1}=\frac{nRT_2}{nRT_2}

Where, R is the gas constant. And n is moles of substance inside the balloon.

In our problem the value of n will be the same for both cases. Also, R is the gas constant.

\frac{P_2V_2}{P_1V_1}=\frac{T_2}{T_1}

Also, we have V_2=22V_1 from the question.

\frac{P_2\times 22V_1}{P_1V_1}=\frac{T_2}{T_1}\\\\\frac{P_2\times 22}{P_1}=\frac{T_2}{T_1}

We need to convert the temperature from \°C to Kelvin.

T_1=12.8\°C\\T_1=12.8+273.15=285.95\\T_2=-47.7\°C\\T_2=-47.7+273.15=225.45

Plug these values we get,

\frac{P_2\times 22}{1}=\frac{225.45}{285.95}\\\\22\times P_2=0.789\\P_2=\frac{0.789}{22}\\P_2=0.0359\ atm.

So, the final pressure inside the balloon will be P_2=0.0359\ atm.

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