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galben [10]
3 years ago
5

What is the value of x in the equation below 1+2e^x+1=9

Physics
1 answer:
GuDViN [60]3 years ago
3 0
<h2>Answer: 1.252</h2>

Explanation:

We are given this equation and we need to find the value of x:

1+2e^x+1=9   (1)

Firstly, we have to clear x:

2e^x=9-1-1  

2e^x=7  

e^x=\frac{7}{2}     (2)

Applying<u> Natural Logarithm</u> on both sides of the equation (2):

ln(e^x)=ln(\frac{7}{2})     (3)

xln(e)=ln(\frac{7}{2})     (4)

According to the Natural Logarithm rules xln(e)=x, so (4) can be written as:

x=ln(\frac{7}{2})     (5)

Finally:

x=1.252    

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A physics student swings a pail of water in a vertical circle 1.0 m in radius at a constant speed. If the water is NOT to spill
love history [14]

Answer:

(A) 3.1 m/s

(B) 2.0 s

Explanation:

At the minimum speed, the force of gravity equals the centripetal force.

mg = m v² / r

v = √(gr)

v = √(9.8 m/s² × 1.0 m)

v = 3.1 m/s

The time is the circumference divided by the speed.

t = (2π × 1.0 m) / (3.1 m/s)

t = 2.0 s

7 0
3 years ago
You stand on top a building 44 m tall with a water balloon. You drop the water balloon from rest. How fast is the balloon moving
Alecsey [184]
<h2>The balloon is moving when it is halfway down the building at 20.78 m/s.</h2>

Explanation:

We have equation of motion v² = u² + 2as

Initial velocity, u = 0 m/s  

Acceleration, a = 9.81 m/s²  

Displacement, s = 0.5 x 44 = 22 m

Substituting  

v² = u² + 2as

v² = 0² + 2 x 9.81 x 22

v² = 431.64

v = 20.78 m/s

Velocity at 22 m = 20.78 m/s

The balloon is moving when it is halfway down the building at 20.78 m/s.

7 0
3 years ago
A parallel-plate capacitor is connected to a battery. After it becomes charged, the capacitor is disconnected from the battery a
Inessa [10]

Answer:

The potential difference between the plates increases

Explanation:

As we know that the capacitance of the capacitor is given by:

q = CV         (1)

where

q = charge

C = capacitance

V = Voltage or Potential Difference

Also, the capacitance of a parallel plate capacitor is given as:

C = \frac{\epsilon_{o}A}{D}           (2)

where

\epsilon_{o} = permittivity of free space or vacuum

A = Area of the plates

D = Separation distance between the plates

Now, from eqn (1) and (2):

V = \frac{qD}{A\epsilon_{o}}

Now, from the above eqn  we can say that:

Potential difference depends directly on the separation distance between the plates of the capacitor and is inversely dependent on the area of the plates of the capacitor.

Therefore, after disconnecting, if the separation between the plates is increased the potential difference across it also increases.

4 0
3 years ago
I NEED HELP ASAP! PLSSSSSSSSSSSSSSSSSSS
OleMash [197]
I’m pretty sure

Part 1; C
Part 2; C

Not 100% sure tho :)
5 0
3 years ago
What is the density of an object that has a mass of 10 g and a volume
Korolek [52]

2g/mL

Explanation:

Given parameters :

Mass = 10g

Volume = 5mL

Unknown:

Density of the object  = ?

Solution:

Density is defined as the mass per unit volume of a body.

  Density = \frac{mass}{Volume}

Now, input the values in the equation:

   Density = \frac{10}{5} = 2g/mL

Learn more:

Density brainly.com/question/5055270

#learnwithBrainly

7 0
3 years ago
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