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maks197457 [2]
3 years ago
10

Heather drops a ball weighing 0.50kg a distance of 2.0m. If the speed of the ball right after it bounces is the same speed of th

e ball right before it bounces, and the interaction time between the ball and the floor was 0.10 seconds, what was the average force of the floor on the ball?
Physics
1 answer:
ki77a [65]3 years ago
7 0
The speed of the ball just before impact was v=√(2gh) = 6.26m/s.  The acceleration is twice this over the time (twice because the second speed is the same in the other direction, meaning the total change in speed is 2V)
a = 12.52/0.10 = 125.2m/s²
The force is F=ma, so F = 0.5kg·125.2m/s² = 62.6N
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