7&8 if u draw it out first it'll help by tons
Weird way to write it but alright! (Sideways)
19pq^-2 x 5pq^6 = ?
These problems are pretty much single operations between each of the variables / constants.
So it's like this:
(19*5)(p*p)(q^-2*q^6) = ?
19*5 is 95.
For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.
p*p is p^2
For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:
-2 + 6 = 4
(The two is negative, because the power is negative 2)
So, q^4.
Our final answer is all of the combined.... like a so:
95p^2q^4
Hello from MrBillDoesMath!
Answer:
Choice B: {1,2,4}
Discussion:
The range of the function is the set of "y" values shown in the table, which is 1,4,4,2. As sets do not contain duplicate elements, the range is {1,2,4). This is Choice B
Thank you,
MrB
Answer:
y = -4/5 x - 3
Step-by-step explanation:
15y = -45 - 12x
5y = -15 - 4x
y = -4/5 x - 3
Answer: ...
Step-by-step explanation:
