Can u please help ASAP
1 answer:
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Answer:
We need a sample size of at least 75.
Step-by-step explanation:
We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of .
So it is z with a pvalue of , so
Now, we find the margin of error M as such
In which is the standard deviation of the population and n is the size of the sample.
The standard deviation is the square root of the variance. So:
With a .95 probability, the sample size that needs to be taken if the desired margin of error is 5 or less is
We need a sample size of at least n, in which n is found when M = 5. So
We need a sample size of at least 75.
Answer:
p < -32
Step-by-step explanation:
<em>Given:</em> p/-8 + 9 > 13
<em>Rewrite:</em> + 9 > 13
<em>Subtract 9 from both sides:</em> > 4
<em>Move the negative (it is a fraction): </em> > 4
<em>Multiply both sides by 8:</em> -p > 32
<em>Times by -1 (-p -> -1p): </em>p > -32
<em>Flip the sign (multiplied by a negative): </em>p < -32
Hope this helps, have a nice day :D