Question

Minimize Q=3x2+3y2​, where x+y=6.

Answer 1

Answer:

$+(x + y) {}^{2} = 6 {}^{2} \\ x {}^{2} + 2xy + y {?}^{2} = 36$

$x {}^{2} + y {}^{2} = 36 - 2xy$

$q = 3(x {}^{2} + y {}^{2} )$

$q = 3(36 - 2xy) = 108 - 6xy$