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Andreyy89
3 years ago
6

Solve each equation by factoring, and state the solutions.

Mathematics
1 answer:
Elenna [48]3 years ago
7 0

Answer:

(a) x^2+25=(x-5)^2+2\times x\times 5=(x-5)^2+10x

(b) x = -5, -5

Step-by-step explanation:

We have given that the equation

(a) x^2+25=0

We have to factorize the equation

We know that (a-b)^2=a^2+b^2-2ab

So (a-b)^2+2ab=a^2+b^2

So x^2+25=(x-5)^2+2\times x\times 5=(x-5)^2+10x

(B) We have given equation x^2+10x+25

It can be factorize as x^2+10x+25=x^2+5x+5x+25=x(x+5)+5(x+5)

Now taking x+5 as common

(x+5)(x+5) = 0

x= -5 , -5

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