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3 years ago

PLLS IM DYING HELP!!!!!!!!

Mathematics

1 answer:

torisob [31]3 years ago

4 0

Answer:

A is 35* and C is 110*

Step-by-step explanation:

I don't know about B

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Graph the exponential function.

Verdich [7]

$\bf \: f(x) = \frac{3}{2} \times {2}^{x} \\ \\ = > \bf \: f(0) = \frac{3}{2} \times {2}^{0} = \frac{3}{2} \times 1 = \frac{3}{2} = 1.5 \\ \\ = > \bf \: f(1) = \frac{3}{2} \times {2}^{1} = 3 \\ \\ = > \bf \: f(2) = \frac{3}{2} \times {2}^{2} = 6 \\ \\ = > \bf \: f( - 1) = \frac{3}{2} \times {2}^{ - 1} = \frac{3}{2} \times \frac{1}{2} = \frac{3}{4} = 0.75 \\ \\ = > \bf \: f( - 2) = \frac{3}{2} \times {2}^{ - 2} = \frac{3}{2} \times \frac{1}{4} = \frac{3}{8} = 0.375$

7 0

3 years ago

Can someone answer this problem, and explain as well?

Alenkasestr [34]

It says that fred has twice as much money which means that if you have to find how much money each of them has you have to divide 54 by 2. the answer is $27

6 0

4 years ago

I REALLY NEED HELP!!!!

Travka [436]

Answer:

...

Step-by-step explanation:

c=64.088 in²

a= 326.851 in²

5 0

3 years ago

Javier has four cylindrical models. The heights, radii, and diagonals of the vertical cross-sections of the models are shown in

Sever21 [200]

Given the heights, radii, and diagonals of the vertical cross-sections of the models, the model in which the lateral surface meet the base at a right angle is the model in which the height, the diameter and the diagonal of the vertical cross-section forms a right triangle.

i.e. the sum of the squares of the height (h) and the diameter (d) gives the square of the diagonal vertical cross-section (l).

For model 1:

radius: 14 cm, thus diameter = 2(14) = 28 cm
height: 48 cm
diagonal: 50 cm

 $d^2+h^2=28^2+48^2 \\ \\ =784+2,304=3,090\neq50^2=l^2$

Thus, the lateral surface of model 1 does not meets the base at right angle.

For model 2:

radius: 6 cm, thus diameter = 2(6) = 12 cm
height: 35 cm
diagonal: 37 cm

[tex]d^2+h^2=12^2+35^2 \\ \\ =144+1,225=1,369=37^2=l^2[/tex]

Thus, the lateral surface of model 2 meets the base at right angle.

For model 3:

radius: 20 cm, thus, diameter = 2(20) = 40 cm
height: 40 cm
diagonal: 60 cm

 $d^2+h^2=40^2+40^2 \\ \\ =1,600+1,600=3,200\neq60^2=l^2$

Thus, the lateral surface of model 3 does not meets the base at right angle.

For model 4:

radius: 24 cm, thus, diameter = 2(24) = 48 cm
height: 9 cm
diagonal: 30 cm

 $d^2+h^2=48^2+9^2 \\ \\ =2,304+81=2,385\neq30^2=l^2$

Thus, the lateral surface of model 3 does not meets the base at right angle.

Therefore, the model in which the lateral surface meets the base at a right angle is model 2 (option b)

8 0

4 years ago

Read 2 more answers

I need help with this question please I’m marking as brainliest to everyone

Ahat [919]

Answer:

First one

Step-by-step explanation:

x² + y² = 9

Is a circle with centre (0,0)

And radius = sqrt(9) = 3

3 0

3 years ago