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3 years ago

I need a bit of help!

Mathematics

2 answers:

g100num [7]3 years ago

8 0

Answer:

The correct answer is where red goes to orange.Blue goes to green and yellow goes to green:

Iteru [2.4K]3 years ago

7 0

Answer:

The correct answer is where red goes to orange.Blue goes to green and yellow goes to green

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How do you solve and show work for <br>624 divided by 8<br>

natali 33 [55]

pls mark as brainlist

Step-by-step explanation:

624 divided by 8 = 78

7 0

3 years ago

Read 2 more answers

A tank initially contains 60 gallons of brine, with 30 pounds of salt in solution. Pure water runs into the tank at 3 gallons pe

adoni [48]

Answer:

the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.

Step-by-step explanation:

The variation of the concentration of salt can be expressed as:

$\frac{dC}{dt}=Ci*Qi-Co*Qo$

being

C1: the concentration of salt in the inflow

Qi: the flow entering the tank

C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)

Qo: the flow going out of the tank.

With no salt in the inflow (C1=0), the equation can be reduced to

$\frac{dC}{dt}=-Co*Qo$

Rearranging the equation, it becomes

$\frac{dC}{C}=-Qo*dt$

Integrating both sides

$\int\frac{dC}{C}=\int-Qo*dt\\ln(\abs{C})+x1=-Qo*t+x2\\ln(\abs{C})=-Qo*t+x\\C=exp^{-Qo*t+x}$

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

$C(0)=exp^{-Qo*0+x}=0.5\\exp^{x} =0.5\\x=ln(0.5)=-0.693\\$

The final equation for the concentration of salt at any given time is

$C=exp^{-3*t-0.693}$

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

$C=exp^{-3*t-0.693}\\(23/60)=exp^{-3*t-0.693}\\ln(23/60)=-3*t-0.693\\t=-\frac{ln(23/60)+0.693}{3}=-\frac{-0.959+0.693}{3}= -\frac{-0.266}{3}=0.088$

5 0

3 years ago

Can someone help please?

seraphim [82]

It is A pls, you can just plug 4x+1 into 4π $r^{2}$

6 0

4 years ago

Match the following items.

max2010maxim [7]

Answer:

1. ∠ABD = 20°.

2. Arc AB = 140°.

3. Arc AD = 40°.

Step-by-step explanation:

Given information: ∠ADB = 70°. BD is diameter.

According to Central angle theorem, the central angle from two chosen points A and B on the circle is always twice the inscribed angle from those two points.

By Central angle theorem,

$\angle DAB=90^{\circ}$

Using angle sum of property in triangle ADB we get,

$\angle ADB+\angle DAB+\angle ABD=180^{\circ}$

$70^{\circ}+90^{\circ}+\angle ABD=180^{\circ}$

$\angle ABD=20^{\circ}$ .

Draw a line segment AO.

In triangle AOD, AO=OD, so

$\angle ODB=\angle OAD=70^{\circ}$

Using angle sum property in triangle AOD,

$\angle AOD+\angle ODA+\angle OAD=180^{\circ}$

$\angle AOD+70^{\circ}+70^{\circ}=180^{\circ}$

$\angle AOD=40^{\circ}$

Therefore length of arc AD is 40°.

The angle AOD and AOB are supplementary angles.

$\angle AOD+\angle AOB=180^{\circ}$

$40^{\circ}+\angle AOB=180^{\circ}$

$\angle AOB=140^{\circ}$

Therefore length of arc AB is 140°.

3 0

4 years ago

Write the equation of a line in standard form that passes through (-2, 5) and is perpendicular to

sdas [7]

Answer:

Step-by-step explanation:

x - 2y = 8

Write this in y = mx +b form

- 2y = -x + 8

Divide the equation by (-2)

$\dfrac{-2y}{-2}=\dfrac{-x}{-2}+\dfrac{8}{-2}\\\\\\y =\dfrac{1}{2}x-4$

Slope = 1/2

The slope of the perpendicular line = -1/m

$=\dfrac{-1}{\dfrac{1}{2}}=1*\dfrac{-2}{1} = -2$

m = -2 , ( -2 , 5)

Equation: y = mx +b

Plug in m = -2 ,x = -2 and y =5

5 = (-2)*(-2) + b

5 = 4 + b

5 - 4 = b

b = 1

Equation of the line:

y = mx +b

y = -2x + 1

7 0

3 years ago