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4 years ago

What’s the inverse of k(x)= x-2/x

Mathematics

1 answer:

omeli [17]4 years ago

4 0

$k - 1(x) = \frac{x + \sqrt{x2 + 8} }{2} \: \frac{x - \sqrt{x2 + 8} }{2}$

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Helppp guys i really don't get it

AysviL [449]

9514 1404 393

Answer:

(b) ... confirm ∠C≅∠E

Step-by-step explanation:

The first step is to read and understand the problem statement. It is asking for a way to prove ΔABC ~ ΔADE by AA similarity. That means you want to show any two of the three ...

∠A≅∠A
∠B≅∠D
∠C≅∠E

For this purpose, lengths of line segments are irrelevant (eliminating the last two answer choices). The fact that ∠A≅∠A is given, so you only need to find an answer choice that will show one of the last two angle congruences.

Obviously, showing ∠B≅∠E (choice A) is not relevant to the problem.

The only answer choice that is relevant to the question is the second one, showing ∠C≅∠E.

8 0

3 years ago

Is this equation an identity? (2x+1)^2-(x+1)^2=3(x+1)^2-1

sergey [27]

Answer:

See below, please

Step-by-step explanation:

Left side

${(2x + 1)}^{2} - {(x + 1)}^{2}$

$= (4 {x}^{2} + 4x + 1) - ( {x}^{2} + 2x + 1)$

$= (4 {x}^{2} - {x}^{2} ) + (4x - 2x) + (1 -1 )$

$= 3 {x}^{2} + 2x$

Right side

$3 \times {(x + 1)}^{2} - 1$

$= 3 \times ( {x}^{2} + 2x + 1) - 1$

$= 3 {x}^{2} + 6x + 3 - 1$

$= 3 {x}^{2} + 6x + 2$

After compared with both sides, we can make a conclusion that

This equation isn't an identity.

6 0

2 years ago

Find the area of the parallelogram that has adjacent sides Bold u equals Bold i minus 2 Bold j plus 2 Bold kand Bold v equals 3

Mice21 [21]

Answer:

The area of the parallelogram is $A=\sqrt{26}$ .

Step-by-step explanation:

Let's rewrite these two vectors:

$u=i-2j+2k$

$v=0i+3j-k$

Let's recall that the area of the parallelogram is the magnitude of the cross product between these vectors.

We can use the Determinant method to find it.

$u \times v=\left[\begin{array}{ccc}i&j&k\\1&-2&2\\0&3&-1\end{array}\right] = i((-2)*(-1)-2*3)-j(1*(-1)-2*0)+k(1*3-(-2)*0)=i(2-6)-j(-1)+k(3)=-4i+j+3k$