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3 years ago

Six and fifty-three hundredths as a decimal- Yes, I'm D-U-M-B!

Mathematics

2 answers:

Ksju [112]3 years ago

3 0

Answer:

6.58

Step-by-step explanation:

ahahahaha lol

saul85 [17]3 years ago

3 0

Answer:

6.58

i hope this helps:)

Step-by-step explanation:

brainliest please?

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jasenka [17]

Simplified it should be 4x^10y^8

3 0

3 years ago

Someone pls pls pls help me

WINSTONCH [101]

Answer:

A, C, D, E

Step-by-step explanation:

According to the rational root theorem, any rational roots will be of the form ...

±(divisor of the constant)/(divisor of the leading coefficient)

The constant is 8, and its divisors are 1, 2, 4, 8.

The leading coefficient is 6, and its divisors are 1, 2, 3, 6.

So, no rational root will have 3 in the numerator, eliminating choices B and F. The remaining choices are possible rational roots:

A, 2/3
C, -8
D, 4
E, -1/6

8 0

3 years ago

Find the volume of cylinder Diameter of base is 11 cm Height of cylinder is 16cm

just olya [345]

Answer:

1520.5 cm³

Step-by-step explanation:

Volume formula for cylinder: V = πr²×h

Radius = 11 ÷ 2

= 5.5cm

Volume = π × 5.5² × 16

=1520.5cm³

3 0

3 years ago

Unit cubes in solid figures

andrey2020 [161]

So what you need to do is find the less he can use.

6 0

3 years ago

Suppose a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%. A cell phon

leva [86]

Answer:

We conclude that the actual percentage of households is equal to 30%.

Step-by-step explanation:

We are given that a consumer group suspects that the proportion of households that have three cell phones NOT known to be 30%.

Their marketing people survey 150 households with the result that 43 of the households have three cell phones.

Let p = proportion of households that have three cell phones NOT known.

So, Null Hypothesis, $H_0$ : p = 30% {means that the actual percentage of households is equal to 30%}

Alternate Hypothesis, $H_A$ : p $\neq$ 30% {means that the actual percentage of households different from 30%}

The test statistics that would be used here One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of households having three cell phones = $\frac{43}{150}$ = 0.29

n = sample of households = 150

So, the test statistics = $\frac{0.29-0.30}{\sqrt{\frac{0.30(1-0.30)}{150} } }$

= -0.27

The value of z test statistic is -0.27.

Also, P-value of the test statistics is given by;

P-value = P(Z < -0.27) = 1 - P(Z $\leq$ 0.27)

= 1 - 0.6064 = 0.3936

Now, at 1% significance level the z table gives critical value of -2.58 and 2.58 for two-tailed test.

Since our test statistic lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the actual percentage of households is equal to 30%.

4 0

3 years ago