Answer:
b. 2.28%.
Step-by-step explanation:
Mean temperatue (μ) = 1000°F
Standard Deviation (σ) = 50
°F
For any temperature value, X, the z-score is given by:
For X= 900°F

A z-score of -2.0 corresponds to the 2.28-th percentile of a normal distribution. Therefore, the probability that X<900 is:

Answer:2=c
Step-by-step explanation:
22=5c+3c-c+8
22-8=5c+3c-c+8-8
14=5c+3c-c+0
14=5c+3c-c
14=8c-2
14=7c
14/7=7c/7
2=c
Check answer by pluging 2 in for c.
5*2+3*2-2+8
=10+6-2+8
=16-2+8
=14+8
=22
The final answer is 2=c
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