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UkoKoshka [18]
3 years ago
6

PLEASE HELP MY TEST IS DUE AT 12:50

Mathematics
1 answer:
Kazeer [188]3 years ago
7 0

Answer:

5. 180-)50+85(

you will get A

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Olivia and Isabella each earn d dollars for each dog she walks. One day, Olivia walks 6 dogs and gets $8 in tips. That same day,
marissa [1.9K]

Answer:

Yes they are equivalent, both equations equals 15d+20

Step-by-step explanation:

We first simplify Olivia's equation

6d + 8 + 9d + 12

1. we combine like terms in the equation: 6d + 8 + 9d + 12

6d+9d

8+12

15d+20

Now we simplify Isabella's

5(3d + 4)

1. we do distributive property

5*3d

5*4

15d+20

If you have any quesitons feel free to ask

8 0
3 years ago
Ok look I need #9 and #19 done
hichkok12 [17]

Answer:

#9 = 24

#19 = -33

Step-by-step explanation:

6 0
3 years ago
Which has the least result? A. 3/4-3/4 B. 3/4+3/4 C. -3/4 + 3/4 D. -3/4-3/4?
MatroZZZ [7]

Answer: D

Step-by-step explanation:

The solution to both A and C would total to about 0. Also, in B both numbers are positives, so that would also be out of the case. If you are looking for the least value, the answer would be D since -3/4 -3/4 would equal -1.5, (or -1 1/2). Therefore, your answer would be D.

Hope that helps :D

4 0
3 years ago
Read 2 more answers
Which is the mode of this data set? 55, 78, 43, 39, 78, 61, 75, 50, 43, 78
vlada-n [284]
Actually the mode is 78. It is 78 because 78 appears 3 times while 43 appears only 2 times.
6 0
4 years ago
Plz give me correct answers ​
son4ous [18]

Answer:

Addition = 3656999

Step-by-step explanation:

Predecessor of number = (Number - 1)

Predecessor of 365000 = 365000 - 1

                                         = 364999

Successor of a number = (Number + 1)

Successor of 3291999 = 3291999 + 1

                                      = 3292000

Now we have have to add the predecessor of 365000 and successor of 3291999,

364999 + 3292000 = 3656999

In other words addition of predecessor of any number and successor of other number will be same as the sum of both the numbers.

5 0
4 years ago
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