We will begin by working through Part (a): Simplify √18
To simplify a square root such as the one above, we must factor out perfect square numbers (this means we must find a number that multiplies to 18 and gives a whole number when we square root it). Using our knowledge that √9 is a perfect square, we should factor out a 9 from 18, as modeled below:
√18 = √(9*2)
We can separate this square root into two square roots multiplied together, as shown below:
√(9*2) = √9 * √2
Now, we should simplify √9, which equals 3, because 3 * 3 = 9.
√9 * √2 = 3 * √2 = 3√2
Therefore, √18 = 3√2.
Now, we can move on to the next problem: √6 * √15.
To begin this problem, we can multiply the square roots together, which means multiplying the numbers under the radical.
√6 * √15 = √(6*15) = √90
To simplify this, we use the same process as above:
√90 = √(10 * 9) = √9 * √10 = 3√10
Note: We know that this fully simplified because we cannot factor out another perfect square number from the number under the radical (10).
Therefore, your two answers are 3√2 and 3√10.
Hope this helps!
Answer:
Below.
Step-by-step explanation:
I'll write sin x as s and cos x as c so we have:
(1 + s +c)/(1 + s - c) = (1 + c)/s
Cross multiplying:
s + s^2 + cs = 1 + s - c + c + cs - c^2
s + s^2 + cs = 1 + s + cs - c^2
s^2 + c^2 + s - s + cs - cs = 1
s^2 + c^2 = 1.
- that is sin^2 x + cos^2 x = 1 which is a known identity.
Therefore the original identity is proved.
Answer:
Square numbers
Step-by-step explanation:
if 1 is squared, you get 1.
if 2 is squared, you get 4.
if 3 is squared, you get 9.
if 4 is squared, you get 16.
And thus square numbers.
