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PilotLPTM [1.2K]
3 years ago
9

A rhombus has sides 10 cm long and an angle of 60 degrees. Find the distance between a pair of opposite sides.

Mathematics
2 answers:
natta225 [31]3 years ago
6 0
<span>angle A + angle B = 180 degrees ... rhombus and h is the perpendicular distance between two parallelsides of the rhombus. ... The side length of the rhombus is equal to 10 feet. Find its area. ... A rhombus has 2 congruent opposite acute angles and two congruent ... area of rhombus = 2 (1 / 2) (10 feet) 2 sin (60 degrees)</span>
DIA [1.3K]3 years ago
4 0
10*sin(60°) = 5√3 ≈ 8.66 . . . cm
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Let f(x) = 13 - |2x+ 1|. Find all x for which f(x) less than or equal to 14
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Answer:

x \leqslant -1\: or \: x  \geqslant  - 1

Step-by-step explanation:

The given function is

f(x) = 13 -  |2x + 1|

We want to find all values of x for which:

f(x) is greater than or equal to 14.

This implies;

13 -  |2x + 1|  \geqslant 14

Subtract 13 from both sides;

-  |2x + 1|  \geqslant 14 - 13

|2x + 1|  \geqslant - 1

By definition of the absolute value function,

- (2x + 1) \geqslant  - 1 \: or \: (2x + 1) \geqslant  - 1

Divide through the first inequality and and reverse the inequality sign:

2x + 1 \leqslant -1 \: or \: 2x + 1 \geqslant  - 1

2x \leqslant -1  - 1 \: or \: 2x  \geqslant  - 1  - 1

2x \leqslant -2 \: or \: 2x  \geqslant  - 2

x \leqslant -1\: or \: x  \geqslant  - 1

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4 years ago
Pls help me solve this questionnnnn
BigorU [14]

9514 1404 393

Answer:

  • arc BC = 60°
  • m∠ADC = 60°
  • m∠AEB = 105°
  • m∠ADP = 45°
  • m∠P = 60°

Step-by-step explanation:

The sum of arcs of a circle is 360°. The given conditions tell us arc BC ≅ arc AB, so the four arcs of the circle have ratios ...

  CB : BA : AD : DC = 2 : 2 : 3 : 5

The sum of ratio units is 2+2+3+5 = 12, so each one stands for 360°/12 = 30°. Then the arc lengths are ...

  arc BC = arc BA = 60° . . . . 2 ratio units each

  arc AD = 90° . . . . . . . . . . . . 3 ratio units

  arc DC = 150° . . . . . . . . . . . .5 ratio units

The inscribed angles are half the measure of the intercepted arcs:

  ∠ADC = (1/2) arc AC = 1/2(120°) = 60°

  ∠ADP = 1/2 arc AD = 1/2(90°) = 45°

The angles at E are half the sum of the measures of the intercepted arcs.

  ∠AEB = (arc AB + arc CD)/2 = (60° +150°)/2 = 105°

Angle P is half the difference of the intercepted arcs.

  ∠P = (arc BD -arc AD)/2 = (210° -90°)/2 = 120°/2 = 60°

__

In summary, ...

  arc BC = 60°

  m∠ADC = 60°

  m∠AEB = 105°

  m∠ADP = 45°

  m∠P = 60°

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