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3 years ago

A rhombus has sides 10 cm long and an angle of 60 degrees. Find the distance between a pair of opposite sides.

2 answers:

6 0

<span>angle A + angle B = 180 degrees ... rhombus and h is the perpendicular distance between two parallelsides of the rhombus. ... The side length of the rhombus is equal to 10 feet. Find its area. ... A rhombus has 2 congruent opposite acute angles and two congruent ... area of rhombus = 2 (1 / 2) (10 feet) 2 sin (60 degrees)</span>

DIA [1.3K]3 years ago

4 0

10*sin(60°) = 5√3 ≈ 8.66 . . . cm

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Here’s another one free 50 points and brainiest, first come first serve!<br> 4x+5-10+3x=57

GarryVolchara [31]

So we have to simplify this equation:
4x+5-10+3x=57
Add like terms:
7x-5=57
Then add 5 to both sides:
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3 years ago

Read 2 more answers

What is the value of the missing angle??

Mice21 [21]

Answer:

39°

Step-by-step explanation:

51° +? = 90°

? = 90° - 51°

? = 39°

Hope it helps you in your learning process.

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2 years ago

A box has a volume of 192 cubic inches, a length that is twice as long as its width, and a height that is 2 inches greater than

ruslelena [56]

Answer:

Therefore the dimension of the cuboid is 8 inches×4 inches ×6 inches.

Step-by-step explanation:

Cuboid : A cuboid is a three dimension shape. The length ,breadth and height of a cuboid are not same.

A cuboid has 6 faces.
A cuboid contains 8 vertices.
A cuboid contains 12 edges .
The total surface area of a cuboid is

= 2(length×breadth+breadth×height+length×height) square units

The dimension of a cuboid is written as length×breadth×height.

The volume is( length×breadth×height) cubic units

Given that the volume of the box is 192 cubic inches.

Let x inches be the width of the cuboid.

Since the length is twice as long as its width.

Then length = 2x inches

Again height is 2 inches longer than width.

Then height = (x+2) inches.

Therefore the volume of the cuboid is

$=[x\times 2x\times (x+2)]$ cubic inches

$=[2x^2(x+2)]$ cubic inches

$=(2x^3+4x^2)$ cubic inches

According to the problem,

$2x^3+4x^2=192$

$\Rightarrow 2x^3+4x^2-192=0$

$\Rightarrow 2(x^3+2x^2-96)=0$

$\Rightarrow (x^3+2x^2-96)=0$

$\Rightarrow x^3-4x^2+6x^2-24x+24x-96=0$

$\Rightarrow x^2(x-4) +6x(x-4)+24(x-4)=0$

$\Rightarrow (x-4)(x^2+6x+24)=0$

Therefore x=4

Since the all zeros of x²+6x+24 =0 is negative.

Therefore breadth = 4 inches

length=(2×4) inches=8 inches

and height = (4+2)inches = 6 inches.

Therefore the dimension of the cuboid is 8 inches×4 inches ×6 inches.

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denis-greek [22]

Answer:

Step-by-step explanation:

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KIM [24]

Answer:

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Step-by-step explanation:

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