The best estimate of the population of trout in the lake is 500 individuals.
The low number of tagged trout recaptured may be because the tags slipped off.
This possibility can be reduced if the student used tags that does not slip off easily.
<h3>Mark and recapture method</h3>
The formula for calculating the estimated number of individuals in the population is given as:
where:
- N = estimated Number of individuals in the population
- M = number of individuals captured and Marked
- C = total number Captured the second time (with and without a mark)
- R= number of individuals Recaptured (those with a mark)
Calculating the estimate trout population:
N = (50*40)/4
N = 50
Therefore, the best estimate of the population of trout in the lake is 500 individuals.
The low number of tagged trout recaptured may be because the tags slipped off.
This possibility can be reduced if the student used tags that does not slip off easily.
Learn more about mark and recapture method at: brainly.com/question/10646744
I believe it's B. That would be the best guess
Answer:
DNA ligase
Explanation:
<em>The biochemist must have left out DNA ligase enzyme.</em>
<u>The DNA ligase enzyme is able to catalyze the formation of phosphodiester bonds and as such, capable of joining strands of DNA together to form a single strand.</u>
The numerous DNA segments of a few nucleotides long observed by the biochemist must have been the replicated product of the lagging DNA strand. The lagging strand is replicated discontinuously in short strands because the DNA polymerase enzyme can only elongate primers in 5' to 3' direction. The short segments are known as Okazaki segments and are usually joined together to form a whole strand by the DNA ligase enzyme.
Hence, the missing component is the DNA ligase.
<span>Answer is d. all of these.
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