So Pythagorean triples will always work with Pythagoras theorem which is a^2 + b2 = c^2 where c is the hypotenuse. So the biggest number (15) will be the hypotenuse so you must do (9^2) + (12^2) and if it is a triple you will get 15^2 so you do 81 + 144 which is 255 and 15^2 is 255 so therefore it is a Pythagorean triple because the numbers satisfy the equation. Hope this helps :)
Answer:
A
Step-by-step explanation:
The slope is positive, the y intercept is -1/2, and and it's going 8 left and 5 up therefore 8/5
Answer:
x^2+y^2 = 3^2
Step-by-step explanation:
We need to eliminate the parameter t
Given:
x = 3 cos t
y = 3 sin t
Squaring the above both equations
(x)^2=(3 cos t)^2
(y)^2 =(3 sin t)^2
x^2 = 3^2 cos^2t
y^2=3^2 sin^2t
Now adding both equations
x^2+y^2=3^2 cos^2t+3^2 sin^2t
Taking 3^2 common
x^2+y^2=3^2 (cos^2t+sin^2t)
We know that cos^2t+sin^2t = 1
so, putting the value
x^2+y^2=3^2(1)
x^2+y^2 = 3^2
Hence the parameter t is eliminated.
Answer:
very easy
Step-by-step explanation:
4(2/3) = 14/3
14/3 ÷ 7
14/3 x 1/7
14/21
2/3
Answer:
The length of side AC is 5 units.
The areas of triangle ABC is 10 square units.
Step-by-step explanation:
From point A (1,3) to point C (1,-2) is 5 units
To check this:
3 - (-2) = 3 + 2 =5
We're subtracting since the point went down (from positive 3 to negative 2)
Now for the area:
Area formula for a triangle: 
bh = ⋅b⋅h
We already found the height (length) : 5
The base is from point C (1,-2) to point B (5,-2), which is 4 units
To check this:
5 - 1 = 4
Now that we have found the base and height, Let's solve:
⋅4⋅5 = ⋅20 = 10
Our area is 10 square units.
Hope that helps :)
