Answer:
the answer will be 1 on the basis of the option
Step-by-step explanation:
and other are 7 5
Add all the displacement vectors together, then find the magnitude of this vector sum.



Summing these vectors gives the resultant displacement

and we have

so the plane ends up about 81.9 km away from its starting position.
Answer:
what do you. red to know I can help you out
B. 8+(-10)
Explanation:
8-10 is -2
If you try all the answers, 8+-10=-2
Step-by-step explanation:
You can imagine this figure as a rectangle and cube
If you want volume of this irregular figure than you have to do it like this:
V(figure)= V(rectangle)+ V(cube)
V(figure)= a*b*c+ a³
V(figure)= 4*3*(I don't see dimension on the left)+ 3³
V(figure)=12*(I don't see dimension on the left)+ 27
And only you have to to do is to set this dimension which I can't see.