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HACTEHA [7]
3 years ago
7

What is the 89,420 divided by 27

Mathematics
2 answers:
disa [49]3 years ago
8 0
The answer is 3311.851851851852
bija089 [108]3 years ago
3 0
Ok. 89420 / 27= 3,311.851 
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When Belinda asked him to what pages his book was opened, he replied that the product of the facing pages was 87,912. To what pa
Liono4ka [1.6K]

Answer:

His book was opened at Page no.296 and Page no.297

Step-by-step explanation:

Let the page number of one page be x

Page number of page facing page no. x = x+1

We are given that the product of the facing pages was 87,912.

So, x(x+1)=87912

x^2+x=87912

x^2+x-87912=0

x^2-296x+297x-87912=0

x(x-296)+297(x-296)=0

(x+297)(x-296)=0

x=296,-297

Since Page no. cannot be negative

So, x=296

x+1=296+1=297

So, his book was opened at Page no.296 and Page no.297

5 0
3 years ago
Can someone please help me I can’t figure this out!!
mixas84 [53]
1. Declarative
2. Interrogative
3. Imperative
4. Interrogative
5. Exclamatory? (Not 100% sure)
6. Exclamatory
7. Declarative
8. Imperative
9. Interrogative
10. Declarative
6 0
3 years ago
HELP ME PLEASE AND THANK YOU
Anna007 [38]

Answer:

The answer is B

Step-by-step explanation:

5 0
3 years ago
Simplify the product using FOIL. (3x + 4)(2x – 6)
Arturiano [62]

Answer:

6x^2 - 10x - 24

Step-by-step explanation:

  1. Do 3x times 2x which is 6x^2
  2. Do 3x times - 6 which is -18x
  3. Do 4 times 2x which is 8x
  4. Do 4 times - 6 which is - 24
  5. You get 6x^2 - 18x + 8x - 24
  6. Simplyify to get the answer
5 0
3 years ago
Read 2 more answers
Consider the differential equation: y′′−8y′=7x+1. Find the general solution to the corresponding homogeneous equation. In your a
Margaret [11]

Answer:

yp = -x/8

Step-by-step explanation:

Given the differential equation: y′′−8y′=7x+1,

The solution of the DE will be the sum of the complementary solution (yc) and the particular integral (yp)

First we will calculate the complimentary solution by solving the homogenous part of the DE first i.e by equating the DE to zero and solving to have;

y′′−8y′=0

The auxiliary equation will give us;

m²-8m = 0

m(m-8) = 0

m = 0 and m-8 = 0

m1 = 0 and m2 = 8

Since the value of the roots are real and different, the complementary solution (yc) will give us

yc = Ae^m1x + Be^m2x

yc = Ae^0+Be^8x

yc = A+Be^8x

To get yp we will differentiate yc twice and substitute the answers into the original DE

yp = Ax+B (using the method of undetermined coefficients

y'p = A

y"p = 0

Substituting the differentials into the general DE to get the constants we have;

0-8A = 7x+1

Comparing coefficients

-8A = 1

A = -1/8

B = 0

yp = -1/8x+0

yp = -x/8 (particular integral)

y = yc+yp

y = A+Be^8x-x/8

3 0
3 years ago
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