Answer: For the sum of 130
First: $90
Second: $40
Step-by-step explanation:
We write equations for each part of this situation.
<u>The Total Charge</u>
Together they charged 1550. This means 1550 is made up of the first mechanics rate for 15 hours and the second's rate for 5 hours. Lets call the first's rate a, so he charges 15a. The second's let's call b. He charges 5b. We add them together 15a+5b=1550.
<u>The Sum of the Rates</u>
Since the first's rate is a and the second is b, we can write a+b=130 since their sum is 130.
We solve for a and b by substituting one equation into another. Solve for the variable. Then substitute the value into the equation to find the other variable.
For a+b=130, rearrange to b=130-a and substitute into 15a+5b=1550.
15a + 5 (130-a)=1550
15a+650-5a=1550
10a+650-650=1550-650
10a=900
a=$90 was charged by the first mechanic.
We substitute to find the second mechanic's rate.
90+b=130
90-90+b=130-90
b= $40 was charged by the second mechanic
3x + 15 because u add all the x and then all real numbers
The third one, 2 to the power of 5 over 6
√2 * 3√2
convert from radical form to exponent form to solve for the same root
( x^m/n = n√x^m )
2^(1/2) * 2^(1/3)
2^{3/6} * 2^{2/6} - find common denominator (6)
6√(2^3) * 6√(2^2) - convert back to radical form
6√(2^3 * 2^2)- combine
6<span>√(</span>2^5)
then convert to exponential form again
~ 2^5/6 ~
Answer:
detailed one
Please mark as the BRAINLIEST
(ㆁωㆁ)
It's c 18, because the diameter is the longest chord so it would be greater than 15.
