There are 4 doughnuts in 1/3 of a dozen
Answer:
Step-by-step explanation:
2:3 boy:teacher 8:12
4:5 teacher:girl 12:15
8:12:15 boy:teacher:girl
Answer:
A
Step-by-step explanation:
let y = f(x) and rearrange making x the subject, that is
y = 
( multiply both sides by x³ )
x³y = 19 ( divide both sides by y )
x³ = 
( take the cube root of both sides )
x = ![\sqrt[3]{\frac{19}{y} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B19%7D%7By%7D%20%7D)
Change y back into terms of x, then
(x) = ![\sqrt[3]{\frac{19}{x} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B19%7D%7Bx%7D%20%7D)
= ![\frac{\sqrt[3]{19} }{\sqrt[3]{x} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B19%7D%20%7D%7B%5Csqrt%5B3%5D%7Bx%7D%20%7D)
→ A
Okay ShallBeTheLast, what we will do will involve a lot of simple plug and play kind of actions.
To start we must notice one number must be negative and the other should be positive, because the multiplied number is a negative.
Next, lets multiply number that have a sum of 10 (keep in mind one has to be negative and the other has to be positive).
-1 * 10 = -10 false
-2 * 12 = -24 false
-3 * 13 = -39 false
notice that no number working and it's only getting farther away.
There is no solution for this that involves to integers.
I think you might of wrote the question backwards.
If that is the case we would run numbers like.....
-1 * (-6) = 7 false
-2 * (-5) = 10 true!!!!
-2 and -5 would work
Answer: There are 152 adults and 87 children.
Step-by-step explanation:
Let x= Number of adults
y= Number of children
As per given, we have
x+y = 239 (i)
15x+5.50y= 2758.50 (ii)
Multiply 5.50 on both sides of (i) , we get
5.50x+5.50y=1314.5 (iii)
Subtract (iii) from (ii), we get
9.5x = 1444
⇒ x = 152
Put value of x in (i) , we get
152+y=239
⇒ y= 239-152
⇒ y= 87
Hence, there are 152 adults and 87 children.
