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mestny [16]
3 years ago
5

How many doughnuts are in 1/3 dozen? Please help meeee!!!!

Mathematics
2 answers:
Eva8 [605]3 years ago
6 0
There are 4 doughnuts in 1/3 of a dozen
zzz [600]3 years ago
6 0
There are 12 donuts in a normal dozen and 13 in a baker's dozen. If you want to know how many in a baker's dozen it's 4.33333 but just 4 donuts in a normal dozen.
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I just need examples of these things, I have to make my own problems and solve them:
poizon [28]
1) x+17=20
x-10=30

2) x/4=20
x/30=2

3) 4(x+5)=40

4) x+3.2=6

5) A pizza place sells pizza for $5 per box. If I had $20 how many pizzas can I buy in all? (5x=20)

Hope this helps! Have a wonderful day.
6 0
3 years ago
The longest side of an obtuse triangle measures 20 cm. The two shorter sides measure x cm and 3x cm.
laiz [17]
The answer to your question would be 6.3
7 0
3 years ago
Read 2 more answers
If f(x) = 2(3x) + 1, what is the value of f(2)?
Over [174]
F(2)=2(3*2)+1
f(2)=2(6)+1
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answer is 13
4 0
3 years ago
To solve the system of equations below, Pedro isolated the variable y in the first equation and then substituted it into the sec
Reil [10]

Answer:

Resulting equation will be 5x²=36.

Step-by-step explanation:

The given equations are 5y = 10x-----(1)

and x²+y²=36------(2)

Now we substitute the value of y from equation (1) into equation (2).

5y = 10x ⇒ y = 2x

Then equation (2) will be x²+(2x)²=36

x²+4x²=36 ⇒ 5x² = 36

So the equation after substitution of the value of y from equation 1 will be 5x² = 36.

8 0
3 years ago
Read 2 more answers
Please help me find the surface area of the triangular prism ( number 3)
antiseptic1488 [7]

Check the picture below.

so the <u>triangular prism</u> is really 3 rectangles and two triangles stacked up to each other at the edges, so if we simply get the area of each figure individually and sum them up, that's the area of the prism.

let's notice, the triangles have a base of 2.4 and a height/altitude of 1.

\bf \stackrel{\textit{2 triangles's area}}{2\left[ \cfrac{1}{2}(2.4)(1) \right]}~~+~~\stackrel{\textit{right rectangle}}{(2\cdot 1.5)}~~+~~\stackrel{\textit{left rectangle}}{(2\cdot 1.7)}~~+~~\stackrel{\textit{bottom rectangle}}{(2\cdot 2.4)} \\\\\\ 2.4+3+3.4+4.8\implies 5.4+8.2\implies 13.6

6 0
3 years ago
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