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mestny [16]
4 years ago
5

How many doughnuts are in 1/3 dozen? Please help meeee!!!!

Mathematics
2 answers:
Eva8 [605]4 years ago
6 0
There are 4 doughnuts in 1/3 of a dozen
zzz [600]4 years ago
6 0
There are 12 donuts in a normal dozen and 13 in a baker's dozen. If you want to know how many in a baker's dozen it's 4.33333 but just 4 donuts in a normal dozen.
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Please help! Find the x intercept and the y intercept of the graph of the equation
soldi70 [24.7K]

Answer:

5y=10-2x

y=(10-2x)/5

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X=(10-5y)/2

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3 years ago
Help! write the set of numbers in set-builder notation: the set of all real numbers except 100​
k0ka [10]

Answer:

Step-by-step explanation:

The set of all real numbers except for 100 in set builder notation (assuming the variable is x) is:

The very first x represents the variable.

The second with the R represents the number. Here, we want all real numbers.

And the third is the constraint. We want all real numbers except for 100.

3 0
3 years ago
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Which step should be completed first in the following problem 4(27÷3²)
Yakvenalex [24]

Answer:

3²

Step-by-step explanation:

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B - Brackets

P - Parenthesis

E - Exponents

M - Multiply

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S - Subtraction

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7 0
4 years ago
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Which expression is equivalent to (7 – 3k) – (4 – 5k) – (6 – 2k)?
gladu [14]

Answer:

The right response is "3(k-1)". A further solution is given below.

Step-by-step explanation:

The given expression is:

⇒ (7 -3k) - (4 - 5k) - (6 - 2k)

On solving the above expression, we get

⇒ 7-3k-4+5k-6+2k

⇒ 7-3k-10+7k

⇒ 3k-3

On taking "3" as common, we get

⇒ 3(k -1 )

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