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mestny [16]
4 years ago
5

How many doughnuts are in 1/3 dozen? Please help meeee!!!!

Mathematics
2 answers:
Eva8 [605]4 years ago
6 0
There are 4 doughnuts in 1/3 of a dozen
zzz [600]4 years ago
6 0
There are 12 donuts in a normal dozen and 13 in a baker's dozen. If you want to know how many in a baker's dozen it's 4.33333 but just 4 donuts in a normal dozen.
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The length of a bridge is 130m. The length of each of roberts paces is 70cm what is the minimum number of the full paces that it
EleoNora [17]
Well if he wants to enjoy the view maybe 30min or so
4 0
3 years ago
Evaluate the following Piecewise Function.<br> Please sturggeling
Anastaziya [24]

Answer:

f(0)=4

f(6) = 8

Step-by-step explanation:

Given

The piece wise function

Solving (a): f(0)

To solve for f(0), we make use of:

f(x) = x + 4

Because: the inequality x < 5 satisfies x = 0

i.e: 0 < 5

So, we have:

f(x) = x + 4

f(0)=0 + 4

f(0)=4

Solving (b): f(6)

To solve for f(6), we make use of:

f(x) = 8

Because: the inequality 5 \le x < 7 satisfies x = 6

i.e: 5 \le 6 < 7

So, we have:

f(6) = 8

3 0
3 years ago
Help me out please..
const2013 [10]

Answer:

D

Step-by-step explanation:

8 0
3 years ago
Suppose u = (1,2,3), v = (2, -3, -4), and w = (1,0,-2). (a) Find u-2v + 3w. (b) Write the vector (3,4,5) as a linear combination
marishachu [46]
<h2>Answer with explanation:</h2>

We are given vectors u,v and w as follows:

      u=(1,2,3)\,\ v=(2,-3,-4),\ and\ w=(1,0,-2)

(a)

Now we are asked to find the value of:

  u-2v+3w

The value is calculated as follows:

u-2v+3w=(1,2,3)-2(2,-3,-4)+3(1,0,-2)\\\\i.e.\\\\u-2v+3w=(1,2,3)+(-2\times 2,-2\times -3,-2\times -4)+(3\times 1,3\times 0,3\times -2)\\\\i.e.\\\\u-2v+3w=(1,2,3)+(-4,6,8)+(3,0,-6)\\\\i.e.\\\\u-2v+3w=(1-4+3,2+6+0,3+8-6)\\\\i.e.\\\\u-2v+3w=(0,8,5)

                              Hence,

                 u-2v+3w=(0,8,5)

(b)

We are asked to represent (3,4,5) as a linear combination of u, v, and w.

Let:

(3,4,5)=au+bv+cw

(3,4,5)=a(1,2,3)+b(2,-3,-4)+c(1,0,-2)

i.e.

(3,4,5)=(a,2a,3a)+(2b,-3b,-4b)+(c,0,-2c)\\\\i.e.\\\\(3,4,5)=(a+2b+c,2a-3b,3a-4b-2c)\\\\i.e.\\\\a+2b+c=3----------(1)

2a-3b=4-------------(2)

3a-4b-2c=5------------(3)

on multiplying equation(1) by 2 an then adding equation (1) to equation (3)

5a=11\\\\i.e.\\\\a=\dfrac{11}{5}

on putting the value of a in equation (2) we get:

2\times \dfrac{11}{5}-3b=4\\\\i.e.\\\\\dfrac{22}{5}-3b=4\\\\i.e.\\\\3b=\dfrac{22}{5}-4\\\\i.e.\\\\3b=\dfrac{2}{5}\\\\i.e.\\\\b=\dfrac{2}{15}

Now on putting the value of a and b in equation (1)

\dfrac{11}{5}+2\times \dfrac{2}{15}+c=3\\\\i.e.\\\\\dfrac{11}{5}+\dfrac{4}{15}+c=3\\\\i.e.\\\\c=3-\dfrac{11}{5}-\dfrac{4}{15}\\\\i.e.\\\\c=\dfrac{3\times 15-11\times 3-4}{15}\\\\i.e.\\\\c=\dfrac{45-33-4}{15}\\\\i.e.\\\\c=\dfrac{8}{15}

Hence, we have:

(3,4,5)=\dfrac{11}{5}(1,2,3)+\dfrac{2}{15}(2,-3,-4)+\dfrac{8}{15}(1,0,-2)\\\\i.e.\\\\(3,4,5)=\dfrac{11}{5}u+\dfrac{2}{15}v+\dfrac{8}{15}w

5 0
4 years ago
If a tires k=0.85, what does this tell you about the tire installed on the car as opposed to the factory-installed tire?
Gala2k [10]

Answer: since I don’t understand this question I’m choosing D

Step-by-step explanation:

8 0
3 years ago
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