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tekilochka [14]
3 years ago
9

Calculate the lower confidence limit​ (LCL) and upper confidence limit​ (UCL) of the mean for each of the following.a. x =265​,

n=459​, σ=50​, and α=0.01b. x=180​, n=308​, σ2equals=100​, and α=0.05LCLequals=​(Round to two decimal places as​ needed.)UCLequals=​(Round to two decimal places as​ needed.)b.LCLequals=​(Round to two decimal places as​ needed.)UCLequals=​(Round to two decimal places as​ needed.)

Mathematics
1 answer:
Alinara [238K]3 years ago
6 0

Answer:

a: 258.09

b: 178.88

Step-by-step explanation:

For a:  Since n > 30, we use a z-value that corresponds to 0.01, or 99% confidence.  This z-value is: 2.575

We have:

x = 265, n = 459, σ = 50.  See the calculation for the error and the construction of the confidence interval on the first attached photo

For b:  Since n > 30, we use a z-value that corresponds to 0.05, or 95% confidence.  This z-value is: 1.96

x = 180, n = 308, σ = 10  (it gives σ² = 100. so σ = 10).  See the calculation for the error and the construction of the confidence interval on the second attached photo

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Answer: a semi circle is half a circle so 35 divided by 2 is 17.5

Step-by-step explanation:

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What’s the answer <br> r+11+ Br= 29
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r= 18/1+b

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2/7m-1/7=3/14 solve step by step
yulyashka [42]

Solution for \frac{2}{7}m - \frac{1}{7} = \frac{3}{14} \ is \ m = \frac{5}{4} \ or \ m = 1\frac{1}{4} \ or \ m = 1.25

<h3>Further explanation</h3>

It is a case about one variable linear quations and we have to solve the equation to get the variable m. There are two ways to solve it!

Our main plan is to isolate the variable m alone at the end of the process on one side of the equation until the variable will be equal to the value on the opposite side.

<u>First way</u>

\frac{2}{7}m - \frac{1}{7} = \frac{3}{14}

Let us add \frac{1}{7} to both sides

\frac{2}{7}m - \frac{1}{7} + \frac{1}{7} = \frac{3}{14} + \frac{1}{7}

\frac{2}{7}m = \frac{3}{14} + \frac{1}{7}

On the right side for the addition operation, we equate the common denominator by multiplying \ \frac{1}{7} \ by \ \frac{2}{2}

\frac{2}{7}m = \frac{3}{14} + \frac{2}{14}

Then we combine terms to get

\frac{2}{7}m = \frac{5}{14}

Divide by the coefficient of m, or in other words, multiply both sides by \frac{7}{2}

\frac{2}{7}m \times \frac{7}{2} = \frac{5}{14} \times \frac{7}{2}

Finally, the solution is obtained as follows

m = \frac{35}{28}

Simplify fractions, both the numerator and denominator are divided equally by 7.

\boxed{ \ m = \frac{5}{4} \ }

Convert into mixed fractions, we get:

\boxed{ \ m = 1 \frac{1}{4} \ }

In decimal form, we get

m = 1 \frac{25}{100} \rightarrow \boxed{ \ m = 1.25 \ }

<u>Second way (a quick way)</u>

\frac{2}{7}m - \frac{1}{7} = \frac{3}{14}

Because the denominators 7 and 14 have LCM = 14, both sides are multiplied by 14 (LCM is the Least Common Multiple)

14 \times \big( \frac{2}{7}m - \frac{1}{7} \big) = 14\times \big( \frac{3}{14} \big)

We use the distributive property of multiplication on the left side

\frac{28}{7}m - \frac{14}{7} = \frac{42}{14}

or it can also directly lead to

4m - 2 = 3

Add 2 to both sides, we get

4m = 5

Divide by the coefficient of m, or in other words, both sides are divided by 4

\boxed{ \ m = \frac{5}{4} \ }

Or, \boxed{ \ m = 1 \frac{1}{4} \ }

Or, m = 1 \frac{25}{100} \rightarrow \boxed{ \ m = 1.25 \ }

Wanna check the solution into the equation?

\big( \frac{2}{7} \times \frac{5}{4} \big) - \frac{1}{7} = \frac{3}{14}

\frac{10}{28} - \frac{1}{7} = \frac{3}{14}

\frac{5}{14} - \frac{2}{14} = \frac{3}{14}

\frac{3}{14} = \frac{3}{14}

Both sides show the same value, so the solution is correct.

Note:

Remember, how to manipulate both sides of the equation with the algebraic properties of equality such as:

  • adding,
  • subtracting,
  • multiplying, and/or
  • dividing both sides of the equation with the same number.

In the form of fractions, the steps that must be considered are

  • equate the denominator,
  • simplify fractions, and
  • for the final answer, convert fractions to mixed fractions or decimal forms

All these processes can occur repeatedly until the isolated variables are obtained on one side of the equation.

<h3>Learn more</h3>
  1. A word problem that forms a single variable linear equation brainly.com/question/1566971
  2. Learn more about the single variable linear equation that has no solution, has one solution, and has infinitely many solutions brainly.com/question/2595790  
  3. Questioning the stages of solving a word problem about one variable linear equations brainly.com/question/2038876
<h3>Answer details  </h3>

Grade : Middle School

Subject : Mathematics

Chapter : Linear Equation in One Variable

Keywords : solve, solution, variable, coefficient, 2/7m - 1/7 = 3/14,  5/4, 1 1/4, 1.125, algebraic properties of equality, one, linear equation, isolated, manipulate, operations, add, subtract, multiply, divide, fraction, equate, denominator, numerator, both sides, decimal

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The answer is 42 because there are 10 adults and
M=4(10)+2
M=40+2
M=42

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Thom has a scale model of his car. Thescale factor is 1 : 12. If the actual car has16-inch wheels, what size are the wheels on t
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Answer: 1.33-inch wheels

Step-by-step explanation:

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So, If the actual car has 16-inch wheels,

The size of the wheels on the scale model will be 16-inch / 12 = 1.33-inch

Thus, Thom's car will have 1.33-inch wheels

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