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Levart [38]
3 years ago
11

X2-9=0

^{2} - 9 = 0 " align="absmiddle" class="latex-formula">
Mathematics
2 answers:
ludmilkaskok [199]3 years ago
4 0
X= 3 or x= -3

this question has 2 solutions due to the variable, hope this helps! pls mark brainliest!
11Alexandr11 [23.1K]3 years ago
4 0
x² - 9 = 0

x² = 9

x₁ = +3
x₂ =  -3
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Find the center, vertices, and foci for the ellipse 25x^2 + 64y^2 = 1600
Alisiya [41]

Answer:

The answer to your question is below

Step-by-step explanation:

Data

Equation               25x² + 64y² = 1600

Process

1.- Divide all the equation by 1600

                             25x²/1600 + 64y²/ 1600 = 1600/1600

-Simplify

                              x²/64 + y²/ 25 = 1

2.- Equation of a horizontal ellipse

                             \frac{x^{2} }{a^{2}} + \frac{y^{2}}{b^{2}} = 1

3.- Find a, b and c

    a² = 64             a = 8

    b² = 25             b = 5

-Calculate c with the Pythagorean theorem

                   a² = b² + c²

-Solve for c

                   c² = a² - b²

-Substitution

                   c² = 8² - 5²

-Simplification

                  c² = 64 - 25

                  c² = 39

-Result

                  c = √13

4.- Find the center

          C = (0, 0)

5.- Find the vertices

          V1 = (-8, 0)     V2 = (8, 0)

6.- Find the foci

          F1 = (-√13, 0)   F2 = (√13, 0)

7 0
3 years ago
Can somebody help me. i don't know if these are right or wrong. If they're wrong can you please correct me? appreciate it​
notsponge [240]

Step-by-step explanation:

it is right

all are right

3 0
3 years ago
Read 2 more answers
What is the ratio for the volumes of two similar cylinders, given that the ratio of their heights and radii is 2:3?
ankoles [38]

Answer:

C IS YOUR ANSER.

Step-by-step explanation:

4 0
3 years ago
What is the completely simplified equivalent of 2/(5+i)?
Bezzdna [24]

namely, let's rationalize the denominator in the fraction, for which case we'll be using the <u>conjugate</u> of that denominator, so we'll multiply top and bottom by its <u>conjugate</u>.

so the denominator is 5 + i, simply enough, its conjugate is just 5 - i, recall that same/same = 1, thus (5-i)/(5-i) = 1, and any expression multiplied by 1 is just itself, so we're not really changing the fraction per se.

\bf \cfrac{2}{5+i}\cdot \cfrac{5-i}{5-i}\implies \cfrac{2(5-i)}{\stackrel{\textit{difference of squares}}{(5+i)(5-i)}}\implies \cfrac{2(5-i)}{\stackrel{\textit{recall }i^2=-1}{5^2-i^2}}\implies \cfrac{2(5-i)}{25-(-1)} \\\\\\ \cfrac{2(5-i)}{25+1}\implies \cfrac{2(5-i)}{26}\implies \cfrac{5-i}{13}

4 0
3 years ago
Which of the following must be true about a perpendicular bisector and the segment it bisects? A. The perpendicular bisector and
Law Incorporation [45]
I am a little rusty on this but i believe it is C
3 0
3 years ago
Read 2 more answers
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