Because LP and NP are the same measure, that means that MP is a bisector. It bisects side LN and it also bisects angle LMN. Where MP meets LN creates right angles. What we have then thus far is that angle LMP is congruent to angle NMP and that angle LPM is congruent to angle NPM and of course MP is congruent to itself by the reflexive property. Therefore, triangle LPM is congruent to triangle NMP and side LM is congruent to side NM by CPCTC. Side LM measures 11.
Is this it or is there more to this question?
Answer:
35 degree angle a cute angle
Answer:
a
Step-by-step explanation:
Given that the terminal side of an <θ intersects the unit circle at the point
![P(\frac{5}{6},\frac{-\sqrt[]{11}}{6})](https://tex.z-dn.net/?f=P%28%5Cfrac%7B5%7D%7B6%7D%2C%5Cfrac%7B-%5Csqrt%5B%5D%7B11%7D%7D%7B6%7D%29)
From the given point P:
![\begin{gathered} x=\frac{5}{6} \\ y=\frac{-\sqrt[]{11}}{6} \\ \text{ s}ince,\text{ x is positive and y is negative, the angle lies in the 4th quadrant} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%3D%5Cfrac%7B5%7D%7B6%7D%20%5C%5C%20y%3D%5Cfrac%7B-%5Csqrt%5B%5D%7B11%7D%7D%7B6%7D%20%5C%5C%20%5Ctext%7B%20s%7Dince%2C%5Ctext%7B%20x%20is%20positive%20and%20y%20is%20negative%2C%20the%20angle%20lies%20in%20the%204th%20quadrant%7D%20%5Cend%7Bgathered%7D)
![\begin{gathered} \tan \theta=\frac{\text{ opposite}}{\text{Adjacent}}=\frac{y}{x} \\ \tan \theta=\frac{\frac{-\sqrt[]{11}}{6}}{\frac{5}{6}}=\frac{-\sqrt[]{11}}{5} \\ \tan \theta=-0.6633 \\ \theta=326.44^0 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctan%20%5Ctheta%3D%5Cfrac%7B%5Ctext%7B%20opposite%7D%7D%7B%5Ctext%7BAdjacent%7D%7D%3D%5Cfrac%7By%7D%7Bx%7D%20%5C%5C%20%5Ctan%20%5Ctheta%3D%5Cfrac%7B%5Cfrac%7B-%5Csqrt%5B%5D%7B11%7D%7D%7B6%7D%7D%7B%5Cfrac%7B5%7D%7B6%7D%7D%3D%5Cfrac%7B-%5Csqrt%5B%5D%7B11%7D%7D%7B5%7D%20%5C%5C%20%5Ctan%20%5Ctheta%3D-0.6633%20%5C%5C%20%5Ctheta%3D326.44%5E0%20%5Cend%7Bgathered%7D)
